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Triangle Inscribed in a circle

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Triangle Inscribed in a circle [#permalink] New post 14 Dec 2006, 05:18
Q) Can any one explain this in some detail...
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 [#permalink] New post 14 Dec 2006, 05:30
The answer should be 11. The angle if o is the center of angle AOC = 120 degrees.

(360-120)/360*d*pi = 24
approximating pi as 3, we get about 12 or 11.
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 [#permalink] New post 14 Dec 2006, 06:09
Getting 11 too
Actual value is 16/sqrt(3)
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 [#permalink] New post 15 Dec 2006, 11:20
equilateral Trngle -> angle A =60 -> angle at the center(angle AOC) =2*inscribed angle =2*60=120 ..this is a theorem ..u can just remember it.

now, 360-120= 240 angle correspondes to 24, length of the given arc.
the circumference is Pi*d=3.14*d corres. to 360 degree that is 36 length.

-> d= 36/Pi=36/3.14 = slightly less than 12..that will be 11 from the answer choices..
  [#permalink] 15 Dec 2006, 11:20
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