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Triangle T has vertices of (-2,6), (6,2) and (0,k) where k

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Triangle T has vertices of (-2,6), (6,2) and (0,k) where k [#permalink] New post 25 Sep 2006, 08:56
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Triangle T has vertices of (-2,6), (6,2) and (0,k) where k is negative. Is k an integer?

(1) The area of T in square units is a multiple of 3
(2) The area of T in square units is a multiple of 5

Last edited by kevincan on 25 Sep 2006, 13:03, edited 1 time in total.
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 [#permalink] New post 25 Sep 2006, 12:48
Ans E.

Area T= 1/2*12*(6+k)


both statements together cannot determine K.
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 [#permalink] New post 26 Sep 2006, 12:09
kevincan wrote:
Any other thoughts?

Imagine a circumscribed rectangle...
  [#permalink] 26 Sep 2006, 12:09
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Triangle T has vertices of (-2,6), (6,2) and (0,k) where k

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