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Triangles [#permalink] New post 12 Dec 2006, 03:36
Q)
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 [#permalink] New post 12 Dec 2006, 06:58
C for me. I use the formula that the ratio of area between the 2 similar shapes = (ratio of the side)^2. That means Area of big ABC / Area of small ABC = (S/s)^2 = 2

So, S/s = sqrt 2. S = s (sqrt2) ans C
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 [#permalink] New post 12 Dec 2006, 07:34
for similar triangles
h/s = H/S where h = height of small triangle and H for other one.
=>h=Hs/S

given,
Area of bigger triangle = 2 * Area of small triangle
=> 1/2*S*H = 2 * 1/2* s*h
=> 1/2*S*H = s*Hs/S
=> S^2 = 2s
=> S = sqrt(2) s

Ans C.
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 [#permalink] New post 12 Dec 2006, 09:51
great reply....thanks
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 [#permalink] New post 12 Dec 2006, 14:01
Posted: Tue Dec 12, 2006 9:34 am Post subject:

--------------------------------------------------------------------------------

for similar triangles
h/s = H/S where h = height of small triangle and H for other one.
=>h=Hs/S

given,
Area of bigger triangle = 2 * Area of small triangle
=> 1/2*S*H = 2 * 1/2* s*h
=> 1/2*S*H = s*Hs/S
=> S^2 = 2s^2 (has typo before)
=> S = sqrt(2) s
  [#permalink] 12 Dec 2006, 14:01
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