commdiver wrote:

I cannot remember the exact question. Even if I did, it is against GMAC's terms of use to divulge official questions. They gave five large numbers and you were asked to find the mean of them. What is an easy way to do that? Say you have 10,964, 5212, 14,230, 4290, and 10,992. Is there a trick to finding the mean of those five numbers?

You can approximate the mean. It should be around 9000 in this case.

10,964 is apprx 11k

5212 is apprx 5k

14,230 is apprx 14k

4290 is apprx 4k

10,992 is apprx 11k

The mean of 4, 5, 11, 11, 14 will be 9 (use deviations concept to figure it out quickly. The deviations concept has been discussed here:

http://www.veritasprep.com/blog/2012/05 ... eviations/)

Since we rounded down many numbers, the mean will be a little more than 9000.

Median of these 5 numbers is 10,964 which is obviously greater than the mean. I doubt you were required to calculate the exact value of the mean.

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