You can approximate the mean. It should be around 9000 in this case.
10,964 is apprx 11k
5212 is apprx 5k
14,230 is apprx 14k
4290 is apprx 4k
10,992 is apprx 11k
The mean of 4, 5, 11, 11, 14 will be 9 (use deviations concept to figure it out quickly. The deviations concept has been discussed here: http://www.veritasprep.com/blog/2012/05 ... eviations/
Since we rounded down many numbers, the mean will be a little more than 9000.
Median of these 5 numbers is 10,964 which is obviously greater than the mean. I doubt you were required to calculate the exact value of the mean.
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