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# Tricky race and distance question

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SVP
Joined: 05 Jul 2006
Posts: 1519
Followers: 5

Kudos [?]: 115 [0], given: 39

Tricky race and distance question [#permalink]  17 Aug 2006, 08:58
Hi everyone i wonder if any one can help me with this one????

Three runners A, B and C run a race, with runner A finishing 12 meters ahead of runner B and 18 meters ahead of runner C, while runner B finishes 8 meters ahead of runner C. Each runner travels the entire distance at a constant speed.

What was the length of the race?

(1) 36 meters (2) 48 meters
(3) 60 meters (4) 72 meters
Senior Manager
Joined: 05 Mar 2006
Posts: 348
Followers: 1

Kudos [?]: 8 [0], given: 0

Is there any other information? It seems as though time or rates are missing.
CEO
Joined: 20 Nov 2005
Posts: 2913
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 18

Kudos [?]: 121 [0], given: 0

48 meters.

Let x = total distance
In the time A finished the race, B covered x-12 and C covered x-18

x/A = (x-12)/B = (x-18)/C

B/C = (x-12)/(x-18)....EQ1

In the time B finished the race, C covered x-8

x/B = (x-8)/C
B/C = x/(x-8).........EQ2

From EQ1 and EQ2 we have
(x-12)/(x-18) = x/(x-8)

x^2 +96 - 20x = x^2 - 18x
x = 48
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Senior Manager
Joined: 05 Mar 2006
Posts: 348
Followers: 1

Kudos [?]: 8 [0], given: 0

I'm surely not ready for QS.

Good one PS!
SVP
Joined: 05 Jul 2006
Posts: 1519
Followers: 5

Kudos [?]: 115 [0], given: 39

OA is 48.........Great Dahiya .... i did it as back solving from the answer choices. but your answer is wut i was exactly looking for but i couldn,t put into action.

Thanks
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