On the day of the performance of a certain play, each ticket that regu

x tickets are sold for $4.5 + $0.5 i.e. $5 each
y - x tickets are sold for $6 + $1 i.e. $7 each

hence total price paid = 5x + 7(y-x) = 7y - 2x

[quote][/quote]


Total of y tickets :

x tickets sold @ 9$ each...
If the price is less than 10 $, then the actual performance day price = half the price + 0.50 $
= ( 4.5 + 0.5 ) x

rest of the tickets = ( y - x ) sold @ 12 $
If the price is more than 10 $ then the actual performance day price = half the price + 1 $
= ( 6 + 1 ) (y - x) = ( y- x ) 7

Total Amount for y tickets = 5x + (y-x) 7
= 7y - 2x

Ans : A

7y-2x.

Answer is A.

Hi All,

This question can be solved by TESTing VALUES.

This prompt tells us some specific changes that occur to the price of a show ticket if you buy the ticket on the day of the show:
1) If the regular price is LESS than $10, then the ticket sells for HALF the price + $0.50
2) If the regular price is GREATER than/equal to $10, then the ticket sells for HALF the price + $1.00

We're told that someone purchases Y tickets on the day of the show; X of the tickets normally sell for $9, while the rest sell for $12. We're asked for the price paid for these tickets.

Looking at the Answers, I can see that they're different enough from one another that I can TEST really small numbers for Y and X.

IF....
Y = 2 tickets
X = 1 ticket that normally costs $9
The other (1) ticket normally costs $12

With the discounts, the prices would be....
(1/2)(9) + $0.50 = $4.50 = $0.50 = $5.00
(1/2)(12) + $1.00 = $6.00 + $1.00 = $7.00

Total Price = $12, when Y = 2 and X = 1

Answer A: 7(2) - 2(1) = 12 This IS a MATCH
Answer B: 12(1) - 7(2) = -2 NOT a match
Answer C: [9(1) + 12(2)]/3 = 11 NOT a match
Answer D: 7(2) + 4(1) = 18 NOT a match
Answer E: 7(2) + 5(1) = 19 NOT a match

Final Answer:

GMAT assassins aren't born, they're made,
Rich

Since x tickets are regularly sold for $9 each, now they are sold for 4.5 + 0.5 = $5 each. Thus, the cost of the x discounted tickets is 5x. Similarly, since the rest of the tickets, i.e., (y - x) tickets, are regularly sold for $12 each, now they are sold for 6 + 1 = $7 each. The cost of the (y - x) discounted tickets is 7(y - x). Therefore, the total amount, in dollars, paid for the y tickets is:

5x + 7(y - x) = 5x + 7y - 7x = 7y - 2x

Answer: A

Regular Price=Rp
Selling Price=Sp

Rp1<$10.00
Sp1=1/2(Rp1)+0.05

Rp2>$10.00
Sp2=1/2(Rp2)+1

Total tickets =y
Sp1= (4.5+0.5)x
Sp2=7(y-x)

Total SP= 5x+7(y-x)=7y-2x

A

Again, the basis of this question is given by quantity x value = amount
It’s like weighed average the concept implicit.
GMAT is about patterns and not tricks. The secret is recognize these patterns always through OFFICIAL questions.

If I see variables in the question that are repeated in the answer choices, I'm going to take that as an invitation to use Plugging In.
Let's make y (the total number of tickets) = 3 and x (the number of $9 tickets) = 1. That means there are two $12 tickets.
The $9 ticket sells for $5. The two $12 tickets sell for $7 each, so $14. All three tickets sell for a total of $19.

Let's check the answer choices:
(A) 7(3) - 2 = 19 Keep it.
(B) 12(3) - 7 = 29 Eliminate.
(C) (9(3) +12)/3 = 13 Eliminate.
(D) 7(3) + 4 = 25 Eliminate.
(E) 7(3) + 5 = 26 Eliminate.

Answer choice A.

Since the price of tickets which were less than $10 is half in addition of $0.5,
The ticket price of x tickets(initial price $9) will be $4.5 + $0.5 = $5

Total tickets = y.
Thus the remaining tickets = y - x

Also, as the price of tickets which were more than $10 is half addition to $1,
The ticket price of y - x tickets(initial price $12) will be $6 + $1 = $7.

Thus total price of tickets = 7(y - x) + 5x
= 7y - 2x

Why you chose 3 tickets total and not other number?

MarceloRamos

I just wanted a number that was easy to work with. Decent chance that 2 would have worked, but we have an answer choice that has 2x, and that also would have made the number each ticket type the same, so I just bumped it up to 3. If we had ended up with more than one answer choice that worked, we would have had to pick new numbers and repeat the process just for the remaining answer choices, but even if that happens, it's still pretty quick and I think the chances of making a careless mistake are pretty low.

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