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New post 27 Aug 2006, 13:50
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A
B
C
D
E

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New post 27 Aug 2006, 16:54
Assume that the length and width are 16 and 20 ( maximum).
The radius is 2 inches; diameter is 4 ; you can accomodate 4 by 5 number of cans

so the maximum number is 20.
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New post 27 Aug 2006, 18:28
Got C also...

Since the height of the can is 12.. you cannot fit multiple cans on top of existing cans.. hence the largest base would be 16x20

which using d=4 (since r=2) you can fit 4x5 = 20 cans.
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New post 28 Aug 2006, 03:54
oooh...that simple..

OA is C.
  [#permalink] 28 Aug 2006, 03:54
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