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TRY this one_PS_Percent_exceeding speed

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Director
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TRY this one_PS_Percent_exceeding speed [#permalink] New post 03 Sep 2007, 22:08
00:00
A
B
C
D
E

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(N/A)

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
will provide with answer later, plz explain

sorry about fuzzy image...
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Manager
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 [#permalink] New post 03 Sep 2007, 22:46
I would answer 30 =)

Total = 100, some exceed, some - do not
From exceeding:
10 = exceeded + ticketed
20 = exceeded + not ticketed

This is my logic.

P.S> Sound like my favorite CR =)
Director
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post 03 Sep 2007, 23:23
IrinaOK wrote:
will provide with answer later, plz explain

sorry about fuzzy image...


its very confusing.

= 10%/(100-20)%

= 12.5%
Director
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post 03 Sep 2007, 23:37
Fistail wrote:
IrinaOK wrote:
will provide with answer later, plz explain

sorry about fuzzy image...


its very confusing.

= 10%/(100-20)%

= 12.5%


nothing is more confusing than answer without explanation............
:=(

no answer would be worse, though...
Director
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post 03 Sep 2007, 23:50
IrinaOK wrote:
will provide with answer later, plz explain

sorry about fuzzy image...


here, I got it,

let`s say
N-total number of motorists
X-total number of those who exceed the speed limit
then,
0,1N=0,8X
X=0,1/0,8=0,125 or 12,5 percent

0,8=1-0,2

Point here is to stay clear about total number of motorists and those who exceed...

Thank you, Fistail!
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 [#permalink] New post 04 Sep 2007, 00:05
Here's how you solve it.
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Director
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Re: TRY this one_PS_Percent_exceeding speed [#permalink] New post 04 Sep 2007, 07:08
there you go.
:-D


IrinaOK wrote:
IrinaOK wrote:
will provide with answer later, plz explain

sorry about fuzzy image...


here, I got it,

let`s say
N-total number of motorists
X-total number of those who exceed the speed limit
then,
0.1N=0.8X
X=0.1/0.8=0.125 or 12.5 percent

0.8=1-0.2

Point here is to stay clear about total number of motorists and those who exceed...

Thank you, Fistail!
Re: TRY this one_PS_Percent_exceeding speed   [#permalink] 04 Sep 2007, 07:08
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