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# Tuesday Q4 - Basketball Team

Author Message
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Manager
Affiliations: CFA Level 2 Candidate
Joined: 29 Jun 2009
Posts: 223
Schools: RD 2: Darden Class of 2012
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Kudos [?]: 40 [0], given: 2

00:00

Difficulty:

5% (low)

Question Stats:

69% (01:54) correct 31% (01:09) wrong based on 33 sessions
9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?
1. 23
2. 30
3. 42
4. 60
5. 126

OA to come
Senior Manager
Affiliations: PMP
Joined: 13 Oct 2009
Posts: 313
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Kudos [?]: 93 [0], given: 37

Agree on 60 , 6C3 * 3C2
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Manager
Joined: 18 Jul 2009
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Schools: South Asian B-schools
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Kudos [?]: 58 [0], given: 37

6C3 x 3C2
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Senior Manager
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How do you get 6C3 * 3C2 ... ?
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+1 D
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Manager
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Kudos [?]: 22 [0], given: 27

Financier wrote:
How do you get 6C3 * 3C2 ... ?

Out of 6 gaurds we have to select 3 -> selection means we use C -> so 6C3

Out of 3 forwards we have to select 2 -> selection means we use C -> so 3C2

Total ways = 6C3 x 3C2 = 60

Hope this helps!
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Manager
Joined: 20 Apr 2010
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Kudos [?]: 43 [1] , given: 36

1
KUDOS
Ok answer is 6C3 * 3C2

lets solve this question as
You have 6 positions and you need to place 3 people on that positions
How many ways you can do that
6C3 ways

Similarly you have 3 positions and you want 2 people to take that position in how many ways they can do that
3C2 ways

and they are mutually exclusive events i.e. there is no dependency of selection of guards on selection of forwards and vice versa
hence they should multiply

Therefore ,it is 6C3 * 3C2

I hope it helps let me know if it does if it does not you can always PM me.....!!!!
and don't forget to give a Kudos if you like the explanation....
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