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Tuesday Q4 - Basketball Team

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Tuesday Q4 - Basketball Team [#permalink] New post 13 Oct 2009, 05:28
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

69% (01:54) correct 31% (01:09) wrong based on 33 sessions
9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?
1. 23
2. 30
3. 42
4. 60
5. 126

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Re: Tuesday Q4 - Basketball Team [#permalink] New post 13 Oct 2009, 09:07
Agree on 60 , 6C3 * 3C2
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Re: Tuesday Q4 - Basketball Team [#permalink] New post 13 Oct 2009, 09:15
6C3 x 3C2 :?
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Re: Tuesday Q4 - Basketball Team [#permalink] New post 18 Aug 2010, 12:17
How do you get 6C3 * 3C2 ... ?
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Re: Tuesday Q4 - Basketball Team [#permalink] New post 18 Aug 2010, 13:41
+1 D :)
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Re: Tuesday Q4 - Basketball Team [#permalink] New post 19 Aug 2010, 01:59
Financier wrote:
How do you get 6C3 * 3C2 ... ?


Out of 6 gaurds we have to select 3 -> selection means we use C -> so 6C3

Out of 3 forwards we have to select 2 -> selection means we use C -> so 3C2

Total ways = 6C3 x 3C2 = 60

Hope this helps!
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Re: Tuesday Q4 - Basketball Team [#permalink] New post 21 Aug 2010, 15:53
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Ok answer is 6C3 * 3C2

lets solve this question as
You have 6 positions and you need to place 3 people on that positions
How many ways you can do that
6C3 ways

Similarly you have 3 positions and you want 2 people to take that position in how many ways they can do that
3C2 ways

and they are mutually exclusive events i.e. there is no dependency of selection of guards on selection of forwards and vice versa
hence they should multiply

Therefore ,it is 6C3 * 3C2

I hope it helps let me know if it does if it does not you can always PM me.....!!!!
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Re: Tuesday Q4 - Basketball Team   [#permalink] 21 Aug 2010, 15:53
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