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# Twelve ambassadors participate in a special meeting. If each

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Manager
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20 Aug 2003, 04:50
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Twelve ambassadors participate in a special meeting. If each of these ambassadors must kiss every other ambassador twice on each cheek, What is the total number of kisses given in the meeting?
a. 24 b. 66 c. 132 d. 264 e. 528
Manager
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20 Aug 2003, 11:03
I have 12C2*4 = 264

Manager
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20 Aug 2003, 11:44
I will go with

12C2 * 8 = 528

for each combination of ambassadors, there will be 8 kisses exchanged - 4 from person A to person B, and 4 from person B to person A.

So I agree with javropu and mistdew, but I think for different reasons.
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20 Aug 2003, 12:36
Each ambssador kisses 11 other ambassodor 4 times ( 2 times each on cheek)

Total kisses = 12 x 11 x 4 = 528
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