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Twelve questions for Christoph!

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Director
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Twelve questions for Christoph! [#permalink] New post 28 Dec 2005, 04:55
Question 5 edited.

[ Question 1 ]

a, b, and c are integers. Is a+b+c=even?

1) a*b*c=even
2) a*c=odd


[ Question 2 ]

N is sum of reciprocal of 91 to100. Which one of the following is less than N?

a) 1/8
b) 1/9
c) 1/10


[ Question 3 ]

The radius of cylinder A is 3 and its height is 5. The radius of cylinder B is 5 and its height is 3. What is the difference between the volume of these two cylinders?


[ Question 4 ]

n is even. Which one of the following is even?

1) (n-1)(n+1)
2) (n+7)(n-2)


[ Question 5 ]

Christoph's friends pick 3 letters out of a, b, c, d, e, f, g, and h. They had to pick only 3 out of them, and 36 combinations are left over.
How many friends Christoph have?

(The order matters here. abc and acb are considered two different combinations.)

[ Question 6 ]

5 people do not have pets. 4 people have one pet each. 4 people have two pets each. 2 people have 3 pets each. Among those who have one pet, two people live in a same house, and the other two live in separate houses. How many houses have pets?


[ Question 7 ]

A transit company has a stastistics table as follow showing how many days it takes to deliver packages.

Transit days 1 2 3 4
No.of packages delivered 10 9 5 X

The average no. of transit days is 3 days, how many packages(X) need 4 days to deliver?


[ Question 8 ]

A farmer has a rectangular field that measures 1000 ft wide by 2000 ft long. There is an untillable strip 20 ft wide on the inside edges of the field. In addition, there is a 30 ft wide untillable strip bisects the field into two squares (approximate). Approximately what percentage of the field is tillable?


[ Question 9 ]

n is positive number. Is n^3>150?

1) (n-2)^3>25
2) (n-1)^3>75


[ Question 10 ]

The formular of calculating the total number of matches in a tournament game is G(n+1)=G(n)+n and G(2) = 1, where n stands for the number of people participating in the tournament. If 20 players are playing in the tournament, how many matches are there?

A. 180 B. 190 C. 200 D. 210 E. 220


[ Question 11 ]

Christoph is setting the table. He has 5 types of cheese and 2 types of fruits. In how many cases are the number of cheese and the number of fruits are same?


[ Question 12 ]

Is (a-5)^4 < (b-5)^4?

1) a<b
2) b-a<5
_________________

Auge um Auge, Zahn um Zahn :twisted: !


Last edited by gamjatang on 28 Dec 2005, 16:49, edited 1 time in total.
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 [#permalink] New post 28 Dec 2005, 06:28
fast answers:

1. c
2. c
3. 30pi
4. 2)
5. 20
6.
7.
8. ~93%
9. B
10. D
11. 5c1*2c1+5c2*2c2
12. c
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 [#permalink] New post 28 Dec 2005, 07:02
Christoph, I agree with your answers so far, but can you please explain questions 5 and 10?

Is the value for 7 an approximation? I've roughly 26,75 packages
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 [#permalink] New post 28 Dec 2005, 11:10
7. i assume its transit days per package...

...then its 29 !
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 [#permalink] New post 28 Dec 2005, 11:49
Christoph,

would you like to explain 5, 7 and 10?

Regards
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 [#permalink] New post 28 Dec 2005, 12:44
allabout wrote:
Christoph,

would you like to explain 5, 7 and 10?

Regards


5. 8c3(all combinations)-36(combinations left over)

7. (10*1+9*2+5*3+4x)/(24+x)=3

10. just insert the numbers and u will see the pattern:

g(2)=1
g(3)=1+2=3
g(4)=3+3=6
g(5)=6+4=10

diff is 2,3,4, etc..

now calc g(20) !
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 [#permalink] New post 28 Dec 2005, 19:25
[ Question 1 ] I have no OA.
[ Question 2 ] I have no OA.
[ Question 3 ] I have no OA.
[ Question 4 ] 2)
[ Question 5 ] 300
[ Question 6 ] 17
[ Question 7 ] 29
[ Question 8 ] 92.5%
[ Question 9 ] I have no OA.
[ Question 10 ] B. 190
[ Question 11 ] 20
[ Question 12 ] E
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Auge um Auge, Zahn um Zahn :twisted: !

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 [#permalink] New post 29 Dec 2005, 01:00
gamjatang wrote:
[ Question 1 ] I have no OA.
[ Question 2 ] I have no OA.
[ Question 3 ] I have no OA.
[ Question 4 ] 2)
[ Question 5 ] 300
[ Question 6 ] 17
[ Question 7 ] 29
[ Question 8 ] 92.5%
[ Question 9 ] I have no OA.
[ Question 10 ] B. 190
[ Question 11 ] 20
[ Question 12 ] E


is question 10 right ? i answere D), which is wrong, but after recalculating, i get 191 ?

g(2)=1
g(3)=1+2=3
g(4)=3+3=6
g(5)=6+4=10

diff is 2,3,4, etc.. diff b/w g(19) and g(20) is 20 ! sum from 2 to 19 is 190 ! but now i have to add g(2), which is 1. i get 191 ! hm ?
_________________

If your mind can conceive it and your heart can believe it, have faith that you can achieve it.

  [#permalink] 29 Dec 2005, 01:00
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