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Two airplanes take off from one airfield at noon. One flies due east a

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Two airplanes take off from one airfield at noon. One flies due east a [#permalink]

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New post 04 Nov 2010, 09:52
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Two airplanes take off from one airfield at noon. One flies due east at 200 miles per hour while the other flies directly northeast at 283 miles per hour. Approximately how many miles apart are the airplanes at 2 p.m.?

A. 166
B. 332
C. 400
D. 483
E. 566
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Re: Two airplanes take off from one airfield at noon. One flies due east a [#permalink]

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New post 04 Nov 2010, 13:49
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In two hours:
the plane flying East will be 400 miles away from airport.
the other plane will be 566 miles away from airport.

566/400 = ~1.4 = ~sqrt(2)

This means that planes formed a right isocheles triangle => sides of such triangles relate as 1:1:sqrt(2) => the planes are 400 miles apart.
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Re: Two airplanes take off from one airfield at noon. One flies due east a [#permalink]

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New post 04 Nov 2010, 19:43
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metallicafan wrote:
Two airplanes take off from one airfield at noon. One flies due east at 200 miles per hour while the other flies directly northeast at 283 miles per hour. Approximately how many miles apart are the airplanes at 2 p.m.?

A. 166
B. 332
C. 400
D. 483
E. 566


This is the diagram I get from the information given. One plane due east 400 miles and other plane north-east 566 miles. Approximate answer is required.
Attachment:
Ques1.jpg
Ques1.jpg [ 4.58 KiB | Viewed 1156 times ]


My problem is that the only time when I know what to do with a 45 degree angle is when it is in a right triangle. But I do not know if this is a right triangle. But the good thing I know about GMAT is that they ask me questions based on some basic concepts only. They may twist the concepts so that it is hard to recognize but they will still test me on the same concepts. So I use this weakness of GMAT to find out whether this is a right triangle.
If it is a right triangle, its other two angles will be 45 each and hence AB will be 400. This means the hypotenuse will be \(400\sqrt{2}\). Since \(\sqrt{2}\) is close to 1.4, 400*1.4 = 560, close enough to 566. Hence the approximate value of AB is indeed 400 and this is a right angled triangle.
Of course, if this triangle weren't right angled, we could still get AB. Substitute 800 in place of 566 and try, if it interests you.
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Re: Two airplanes take off from one airfield at noon. One flies due east a   [#permalink] 04 Nov 2010, 19:43
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