Find all School-related info fast with the new School-Specific MBA Forum

It is currently 24 Jul 2014, 12:04

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Two cars A and B start from Boston and New York respectively

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
1 KUDOS received
Senior Manager
Senior Manager
avatar
Joined: 21 Jan 2010
Posts: 348
Followers: 0

Kudos [?]: 61 [1] , given: 12

Two cars A and B start from Boston and New York respectively [#permalink] New post 28 Apr 2012, 19:50
1
This post received
KUDOS
9
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  65% (medium)

Question Stats:

45% (04:49) correct 55% (03:15) wrong based on 202 sessions
Two cars A and B start from Boston and New York respectively simultaneously and travel towards each other at constant speeds along the same route. After meeting at a point between Boston and New York the two cars A and B proceed to their respective destinations of New York and Boston. Car A reaches New York 40 minutes after the two cars have met and Car B reaches Boston 90 minutes after they have met. How long did Car A take to cover the distance between Boston and New York?

A. 1 hour
B. 1 hour 10 minutes
C. 2 hours 30 minutes
D. 1 hour 40 minutes
E. 2 hours 10 minutes
[Reveal] Spoiler: OA
Expert Post
14 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 18727
Followers: 3239

Kudos [?]: 22338 [14] , given: 2615

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 29 Apr 2012, 23:53
14
This post received
KUDOS
Expert's post
vdadwal wrote:
Two cars A and B start from Boston and New York respectively simultaneously and travel towards each other at constant speeds along the same route. After meeting at a point between Boston and New York the two cars A and B proceed to their respective destinations of New York and Boston. Car A reaches New York 40 minutes after the two cars have met and Car B reaches Boston 90 minutes after they have met. How long did Car A take to cover the distance between Boston and New York?

A. 1 hour
B. 1 hour 10 minutes
C. 2 hours 30 minutes
D. 1 hour 40 minutes
E. 2 hours 10 minutes


Look at the diagram below:
Attachment:
Boston - New York.png
Boston - New York.png [ 4.56 KiB | Viewed 4901 times ]

The rate of car A is a and the rate of B is b;
The distance covered by A before the meeting point is x and the distance covered by B before the meeting point is y;
Time before meeting t.

Since car A covered the distance of y in 40 minutes then the rate of car A = distance/time = a=\frac{y}{40}, but the same distance of y was covered by car B in t minutes, so y=bt --> a=\frac{bt}{40};

Since car B covered the distance of x in 90 minutes then the rate of car B = distance/time = b=\frac{x}{90}, but the same distance of x was covered by car A in t minutes, so x=at --> b=\frac{at}{90};

Substitute b in the first equation: a=\frac{at}{90}*\frac{t}{40} --> reduce by a and cross-multiply: t^2=3600 --> t=60 minutes, hence it took car A 60+40=100 minutes to cover the whole distance.

Answer: D.

Hope it's clear.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

9 KUDOS received
Intern
Intern
avatar
Joined: 07 Feb 2011
Posts: 9
Followers: 0

Kudos [?]: 14 [9] , given: 0

Re: speed distance time [#permalink] New post 29 Apr 2012, 00:24
9
This post received
KUDOS
If two objects A and B start from opposite points and, after having met en route, reach their respective destinations in a and b mins (or any other measure of time) respectively, then the ratio of their speeds

\frac{Sa}{Sb} = \sqrt{\frac{Time taken by B}{Time taken by A}}

Hence:

\frac{Sa}{Sb} = \sqrt{\frac{90}{40}}
\frac{Sa}{Sb} = \frac{3}{2}

Hence, time taken by A to cover the same distance which B covers in 90 minutes is:

Ta = \frac{90*2}{3}
Ta = 60 minutes

Hence, total time of A = 40 minutes + 60 minutes = 1 hour 40 minutes
Expert Post
2 KUDOS received
Veritas Prep GMAT Instructor
User avatar
Joined: 16 Oct 2010
Posts: 4573
Location: Pune, India
Followers: 1029

Kudos [?]: 4469 [2] , given: 162

Re: speed distance time [#permalink] New post 18 Mar 2013, 01:56
2
This post received
KUDOS
Expert's post
eaakbari wrote:
paragkan wrote:
If two objects A and B start from opposite points and, after having met en route, reach their respective destinations in a and b mins (or any other measure of time) respectively, then the ratio of their speeds

\frac{Sa}{Sb} = \sqrt{\frac{Time taken by B}{Time taken by A}}

Hence:

\frac{Sa}{Sb} = \sqrt{\frac{90}{40}}
\frac{Sa}{Sb} = \frac{3}{2}

Hence, time taken by A to cover the same distance which B covers in 90 minutes is:

Ta = \frac{90*2}{3}
Ta = 60 minutes

Hence, total time of A = 40 minutes + 60 minutes = 1 hour 40 minutes


Great formula.

I solved the question the conventional way but took a whopping 4.5 minutes to do so.
It took 2 minutes to figure out itself. :shock:

The formula will surely help.


There are many formulas that you can learn to cover the various specific question demands but it is not feasible to remember them all. It will be much better if you try to logically figure it out in case you are unable to recall the formula at crunch time.

Think of the situation when they meet:

(Boston) A->____________________M_________<-B (New York)

A starts from Boston and B from New York simultaneously. After some time, say t mins of travel, they meet at M. Since A covers the entire distance of Boston to New York in (t + 40) mins and B covers it in (t + 90) mins, A is certainly faster than B and hence the point M is closer to New York.

Distance between Boston and M/Distance between M and New York = Time taken to go from Boston to M/Time taken to go from M to New York = t/40 = 90/t
t = 60 mins
(distance varies directly with time)

So A takes 60 mins + 40 mins = 1 hr 40 mins to cover the entire distance.
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Save $100 on Veritas Prep GMAT Courses And Admissions Consulting
Enroll now. Pay later. Take advantage of Veritas Prep's flexible payment plan options.

Veritas Prep Reviews

Expert Post
2 KUDOS received
Veritas Prep GMAT Instructor
User avatar
Joined: 16 Oct 2010
Posts: 4573
Location: Pune, India
Followers: 1029

Kudos [?]: 4469 [2] , given: 162

Re: speed distance time [#permalink] New post 17 Mar 2014, 20:19
2
This post received
KUDOS
Expert's post
idinuv wrote:
VeritasPrepKarishma wrote:
Distance between Boston and M/Distance between M and New York = Time taken to go from Boston to M/Time taken to go from M to New York = t/40 = 90/t
t = 60 mins
(distance varies directly with time)


Do you mean to say:
\frac{Distance Between Boston And M}{Distance Between M And New York} = \frac{Time Taken To Go From Boston To M}{Time Taken To Go From M to New York} = \frac{t}{40} = \frac{90}{t}

Can you please explain how have you got distance as 't'. Time taken has been assumed as 't'.


I did not take the distance at 't'. 't' has been assumed to be the time taken for them to meet after starting from their respective starting points.

When speed of an object stays constant, the ratio of distance traveled is equal to the ratio of time taken. In 1 hr, it travels 20 miles. In 2 hrs, 40 miles and so on... For more on the use of ratios in TSD, check: http://www.veritasprep.com/blog/2011/03 ... os-in-tsd/

Now look at only car A.
It travels from Boston to M in t mins and from M to New York in 40 mins.

\frac{Time Taken ByATo Go From Boston To M}{Time TakenByA To Go From M to New York} = \frac{t}{40}

But, we discussed that ratio of distances will be the same as ratio of Time take so
\frac{Distance Between Boston And M}{Distance Between M And New York} = \frac{Time Taken ByATo Go From Boston To M}{Time TakenByA To Go From M to New York} = \frac{t}{40}

Similarly, considering car B, we get
\frac{Distance Between Boston And M}{Distance Between M And New York} = \frac{Time Taken ByATo Go From Boston To M}{Time TakenByA To Go From M to New York} = \frac{90}{t}

Note that both t/40 and 90/t are the ratios of \frac{Distance Between Boston And M}{Distance Between M And New York} so they will be equal.

Does it all make sense now?
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Save $100 on Veritas Prep GMAT Courses And Admissions Consulting
Enroll now. Pay later. Take advantage of Veritas Prep's flexible payment plan options.

Veritas Prep Reviews

Expert Post
1 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 18727
Followers: 3239

Kudos [?]: 22338 [1] , given: 2615

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 30 Apr 2012, 01:31
1
This post received
KUDOS
Expert's post
kartik222 wrote:
hi Bunuel,

Thanks a lot for the explanation. :)

Is there any general concept I can follow in these speed, rate, and distance questions. I mean looking at the question I had no fixed approach towards the answer because I saw felt information was too little.

It would more helpful if you can share how do YOU approach these type questions.

p.s: Kudos +1

thanks,


This post might help: distance-speed-time-word-problems-made-easy-87481.html
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Expert Post
1 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 18727
Followers: 3239

Kudos [?]: 22338 [1] , given: 2615

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 30 Apr 2012, 03:05
1
This post received
KUDOS
Expert's post
paragkan wrote:
kartik222 wrote:
hi Paragkan,

how did you get to the formula related to ratio of speed at the first place?

thanks,


I read that formula in some book. I have not derived it


You can derive it from the formulas in my solution:

a=\frac{bt}{40} --> t=\frac{40a}{b};
b=\frac{at}{90} --> t=\frac{90b}{a};

So, \frac{40a}{b}=\frac{90b}{a} --> \frac{a}{b}=\frac{3}{2}.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Manager
Manager
avatar
Joined: 27 Dec 2011
Posts: 50
Followers: 0

Kudos [?]: 3 [0], given: 10

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 29 Apr 2012, 22:25
hi Paragkan,

how did you get to the formula related to ratio of speed at the first place?

thanks,
Senior Manager
Senior Manager
avatar
Joined: 21 Jan 2010
Posts: 348
Followers: 0

Kudos [?]: 61 [0], given: 12

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 29 Apr 2012, 22:27
I think he is just applying the formulae speed = distance/time . So the train travelling from NY to boston is travelling at a greater speed.
Manager
Manager
avatar
Joined: 27 Dec 2011
Posts: 50
Followers: 0

Kudos [?]: 3 [0], given: 10

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 29 Apr 2012, 22:31
Hi Vdadwal,

I tried applying speed, time and distance formula too but I could reach the formula paragkan has stated.

thanks,
Manager
Manager
avatar
Joined: 27 Dec 2011
Posts: 50
Followers: 0

Kudos [?]: 3 [0], given: 10

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 30 Apr 2012, 00:28
hi Bunuel,

Thanks a lot for the explanation. :)

Is there any general concept I can follow in these speed, rate, and distance questions. I mean looking at the question I had no fixed approach towards the answer because I saw felt information was too little.

It would more helpful if you can share how do YOU approach these type questions.

p.s: Kudos +1

thanks,
Intern
Intern
avatar
Joined: 07 Feb 2011
Posts: 9
Followers: 0

Kudos [?]: 14 [0], given: 0

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 30 Apr 2012, 02:46
kartik222 wrote:
hi Paragkan,

how did you get to the formula related to ratio of speed at the first place?

thanks,


I read that formula in some book. I have not derived it
Manager
Manager
User avatar
Joined: 24 Mar 2010
Posts: 81
Followers: 0

Kudos [?]: 14 [0], given: 134

Re: speed distance time [#permalink] New post 30 Dec 2012, 07:16
paragkan wrote:
If two objects A and B start from opposite points and, after having met en route, reach their respective destinations in a and b mins (or any other measure of time) respectively, then the ratio of their speeds

\frac{Sa}{Sb} = \sqrt{\frac{Time taken by B}{Time taken by A}}

Hence:

\frac{Sa}{Sb} = \sqrt{\frac{90}{40}}
\frac{Sa}{Sb} = \frac{3}{2}

Hence, time taken by A to cover the same distance which B covers in 90 minutes is:

Ta = \frac{90*2}{3}
Ta = 60 minutes

Hence, total time of A = 40 minutes + 60 minutes = 1 hour 40 minutes


Great formula.

I solved the question the conventional way but took a whopping 4.5 minutes to do so.
It took 2 minutes to figure out itself. :shock:

The formula will surely help.
_________________

- Stay Hungry, stay Foolish -

Intern
Intern
avatar
Joined: 27 Dec 2012
Posts: 11
Followers: 0

Kudos [?]: 0 [0], given: 10

CAT Tests
Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 14 Mar 2013, 02:48
Bunuel wrote:
vdadwal wrote:
Two cars A and B start from Boston and New York respectively simultaneously and travel towards each other at constant speeds along the same route. After meeting at a point between Boston and New York the two cars A and B proceed to their respective destinations of New York and Boston. Car A reaches New York 40 minutes after the two cars have met and Car B reaches Boston 90 minutes after they have met. How long did Car A take to cover the distance between Boston and New York?

A. 1 hour
B. 1 hour 10 minutes
C. 2 hours 30 minutes
D. 1 hour 40 minutes
E. 2 hours 10 minutes


Look at the diagram below:
Attachment:
Boston - New York.png

The rate of car A is a and the rate of B is b;
The distance covered by A before the meeting point is x and the istance covered by B before the meeting point is y;
Time before meeting t.

Since car A covered the distance of y in 40 minutes then the rate of car A = distance/time = a=\frac{y}{40}, but the same distance of y was covered by car B in t minutes, so y=bt --> a=\frac{bt}{40};

Since car B covered the distance of x in 90 minutes then the rate of car B = distance/time = b=\frac{x}{90}, but the same distance of x was covered by car A in t minutes, so x=at --> b=\frac{at}{90};

Substitute b in the first equation: a=\frac{at}{90}*\frac{t}{40} --> reduce by a and cross-multiply: t^2=3600 --> t=60 minutes, hence it took car A 60+40=100 minutes to cover the whole distance.

Answer: D.

Hope it's clear.

Bunuel,
You are a genius Hats off to you. I can die to have brains like you.
Expert Post
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 18727
Followers: 3239

Kudos [?]: 22338 [0], given: 2615

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 14 Jul 2013, 23:58
Expert's post
Senior Manager
Senior Manager
User avatar
Joined: 13 May 2013
Posts: 476
Followers: 1

Kudos [?]: 44 [0], given: 134

Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 04 Aug 2013, 12:50
Two cars A and B start from Boston and New York respectively simultaneously and travel towards each other at constant speeds along the same route. After meeting at a point between Boston and New York the two cars A and B proceed to their respective destinations of New York and Boston. Car A reaches New York 40 minutes after the two cars have met and Car B reaches Boston 90 minutes after they have met. How long did Car A take to cover the distance between Boston and New York?

Both cars leave at the same time
Both cars travel at constant speed

Stealing a useful piece of information from Paragkan:

If two objects A and B start from opposite points and, after having met en route, reach their respective destinations in a and b mins (or any other measure of time) respectively, then the ratio of their speeds

ratio of speed: (a/b) = sq. rt(b/a)
sq. rt(b/a)
sq. rt(90/40)
sq. rt(3/2)

So, for every three units of distance A travels, B travels two. Because we know the ratio of speed and the time it took B to travel the distance A hasn't yet covered, we can find the time it took A to cover the distance B did in 90 minutes.

90*(2/3) where 2/3 represents the lesser amount of time it took A to travel the distance B did in 90 minutes.

= 60 minutes.

Therefore, A took 40 minutes to travel the first portion then 60 minutes to travel the distance B did in 90 minutes. A spent (40+60)=100 minutes on the road.

D. 1 hour 40 minutes

Bunuel, in your explanation, for a you had speed of a=y/40 which I understand, but why then do you solve for the distance of b? Why wouldn't I do this in other similar problems I have solved? thanks!
Manager
Manager
avatar
Status: Persevering
Joined: 15 May 2013
Posts: 223
Location: India
Concentration: Technology, Leadership
GMAT Date: 08-02-2013
GPA: 3.7
WE: Consulting (Consulting)
Followers: 0

Kudos [?]: 46 [0], given: 34

GMAT ToolKit User
Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 05 Aug 2013, 10:26
To put it in simpler terms

Let x be the distance traveled by A and y be the distance traveled by B and let a and b be the respective rates

So as before meeting they travel for the same time. Let that time be t

Now,
we can say that as distance traveled by A before meeting B is the same as the distance traveled by B after meeting A and vice-verse

So, 1) a*t=b*90
2) b*t=a*40

Now to solve this, It depends upon what is required: We can either substitute value of b to get t
or divide 1)/2) to get ratio of speeds.

If we follow the first approach we get
a*t=b*90 => a=90b/t ---(1)
from 2nd we get b=a*40/t ---(2)
a=90*a*40/t*t
=>t*t=3600 t=60 mins

On the other hand if we were to divide it we would get the formula for speed ratios
a/b=b/a*(90/40)
a^2/b^2=90/40
=>a/b=3/2 and this is how the formula was reached at.
_________________

--It's one thing to get defeated, but another to accept it.

Intern
Intern
avatar
Joined: 21 Mar 2013
Posts: 44
GMAT Date: 03-20-2014
Followers: 0

Kudos [?]: 9 [0], given: 56

GMAT ToolKit User
Re: speed distance time [#permalink] New post 17 Mar 2014, 06:42
VeritasPrepKarishma wrote:
Distance between Boston and M/Distance between M and New York = Time taken to go from Boston to M/Time taken to go from M to New York = t/40 = 90/t
t = 60 mins
(distance varies directly with time)


Do you mean to say:
\frac{Distance Between Boston And M}{Distance Between M And New York} = \frac{Time Taken To Go From Boston To M}{Time Taken To Go From M to New York} = \frac{t}{40} = \frac{90}{t}

Can you please explain how have you got distance as 't'. Time taken has been assumed as 't'.
Intern
Intern
avatar
Joined: 21 Mar 2013
Posts: 44
GMAT Date: 03-20-2014
Followers: 0

Kudos [?]: 9 [0], given: 56

GMAT ToolKit User
Re: Two cars A and B start from Boston and New York respectively [#permalink] New post 17 Mar 2014, 21:10
Yes. Thanks for the prompt reply.
Re: Two cars A and B start from Boston and New York respectively   [#permalink] 17 Mar 2014, 21:10
    Similar topics Author Replies Last post
Similar
Topics:
Experts publish their posts in the topic Two trains A and B starting from two points and travelling fra 4 18 Nov 2013, 07:48
A and B start from Opladen and Cologne respectively at the sammy04 3 05 Oct 2013, 06:59
Car Possible In New York? johnnyx9 30 23 Apr 2007, 07:43
York? Boston? yogil80 0 12 Nov 2006, 23:04
Two cars A and B start from Boston and New York respectively cloaked_vessel 8 13 Mar 2005, 09:19
Display posts from previous: Sort by

Two cars A and B start from Boston and New York respectively

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.