Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: Two coins are tossed with probability landing at Head not [#permalink]
24 Nov 2012, 11:19

I got it right but i'm not sure if my guess was right. As i looked at it, in (1) we can know what the odds of getting heads/tails are. in (2) we could not know what the odds are for each one, only for both combined, that's why (2) doesn't help at all.... did I get it right?

Re: Two coins are tossed with probability landing at Head not [#permalink]
26 Nov 2012, 06:35

ronr34 wrote:

I got it right but i'm not sure if my guess was right. As i looked at it, in (1) we can know what the odds of getting heads/tails are. in (2) we could not know what the odds are for each one, only for both combined, that's why (2) doesn't help at all.... did I get it right?

Yes, that is correct! _________________

Aeros "Why are you trying so hard to fit in when you were born to stand out?" "Do or do not. There is no 'try'..."

Re: Two coins are tossed with probability landing at Head not [#permalink]
25 May 2014, 10:11

(1) Suppose we have a coin with 3 Head faces and 1 Tail face, a special biased coin.

Therefore probability of getting head in two tosses = 3/4*3/4= 9/16.

Therefore 1 is sufficient. _________________

Piyush K ----------------------- Our greatest weakness lies in giving up. The most certain way to succeed is to try just one more time. ― Thomas A. Edison Don't forget to press--> Kudos My Articles: 1. WOULD: when to use?| 2. All GMATPrep RCs (New) Tip: Before exam a week earlier don't forget to exhaust all gmatprep problems specially for "sentence correction".

Re: Two coins are tossed with probability landing at Head not [#permalink]
04 Jun 2014, 04:39

aeros232 wrote:

ronr34 wrote:

I got it right but i'm not sure if my guess was right. As i looked at it, in (1) we can know what the odds of getting heads/tails are. in (2) we could not know what the odds are for each one, only for both combined, that's why (2) doesn't help at all.... did I get it right?

Yes, that is correct!

Hi,

Could you please explain the second statement a bit more clearly ? I mean why 2 is not sufficient?

Re: Two coins are tossed with probability landing at Head not [#permalink]
04 Jun 2014, 08:11

Expert's post

aniteshgmat1101 wrote:

aeros232 wrote:

ronr34 wrote:

I got it right but i'm not sure if my guess was right. As i looked at it, in (1) we can know what the odds of getting heads/tails are. in (2) we could not know what the odds are for each one, only for both combined, that's why (2) doesn't help at all.... did I get it right?

Yes, that is correct!

Hi,

Could you please explain the second statement a bit more clearly ? I mean why 2 is not sufficient?

Thanx in advance.

Two coins are tossed with probability landing at Head not equal to 0.5. What is the probability of getting two Heads out of two tosses?

Say the probability of heads is p and the probability of tails is 1-p.

(1) The probability of getting head is 3 times that of getting tails --> p=3(1-p) --> p=3/4 --> the probability of getting two Heads out of two tosses = 3/4*3/4. Sufficient.

(2) Tossed two times, the probability of getting one Head and one Tail is 2/9 --> P(HT)=2*p(1-p)=2/9 (we multiply by to because one Head and one Tail can occur in two ways HT and TH). We get two value for p. Not sufficient.

Answer: A.

P.S. This is a poor quality question, since the values of p differ from (1) and (2), while on the GMAT, two data sufficiency statements always provide TRUE information and these statements never contradict each other or the stem. _________________

Originally posted on MIT Sloan School of Management : We are busy putting the final touches on our application. We plan to have it go live by July 15...