gmat2me2 wrote:

HongHu wrote:

What if one of the couples sits together and the other doesn't?

But we were asked in the question how many ways the 2 couples cannot sit together....So I subtracted 1 - (Probablity of 2 couples sitting together)....

So you mean to say that 1 couple sit together but the other aint...Isnt it ?

So that could be 4!*2 ...Is this correct?

So the each of the 2 couples can sit together in 4!*2! ways = 48 ways

Since there are 2 couple = 96 ways.

But this included both the couples sitting toghether = 3!*2!*2! = 24 (I was confused at this point but now I think I understand the question)

96-24 = 72 ways only one couple can sit togther

probability of Neither of couple sitting together is= 72/120 = 3/5