lfox2 wrote:

Two cyclists start biking from a trailâ€™s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?

a) 2 hours

b) 4 Â½ hours

c) 5 Â¾ hours

d) 6 hours

e) 7 Â½ hours

A bit unclear question... what exactly does this "3 hours apart" means...

It is written that the second cyclist starts 3 hours after the first, so is this the repeated info or not? if yes, the answer is 4.5 hours.

A: rate=10/1.....t=t.....d=d

B: rate=6/1.......t=t+3 (started 3 hours earlier).....d=d

Construct two equations:

10t=d

6t+18=d....merge

6t+18=10t

-4t=-18

t=4.5 hours....

But the question is bit unclear to me.....