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Two fair dices are rolled. Find the probability that the

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VP
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Two fair dices are rolled. Find the probability that the [#permalink] New post 27 Nov 2005, 16:10
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Two fair dices are rolled. Find the probability that the number showing on the first die is less than the number showing on the second die.
Director
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 [#permalink] New post 27 Nov 2005, 16:40
Probability that two numbers are same
= 1/6 * 1/6 * 6 = 1/6

Probability that either one is bigger
= 1 - 1/6 = 5/6

Probability that first is bigger
= 5/6 * 1/2 = 5/12
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Auge um Auge, Zahn um Zahn :twisted: !

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Re: Probability: Dice [#permalink] New post 27 Nov 2005, 20:49
total outcome = (6x6) = 36
the number showing on the first die is less than the number showing on the second die, desired outcomes = 15
prob = 15/36 = 5/12
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 [#permalink] New post 27 Nov 2005, 22:07
Die 1 = 1, Die 2 - 5 cases
Die 1 = 2, Die 2 - 4 cases
Die 1 = 3, Die 2 - 3 cases
Die 1 = 4, Die 2 - 2 cases
Die 1 = 5, Die 2 - 1 case

Total = 15 cases
P = 15/36 = 5/12
Director
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 [#permalink] New post 28 Nov 2005, 05:35
Total outcomes = 36.

Events = 12, 13, 14, 15, 16, 23, 24, 25, 26, 34, 35, 36, 45, 46, 56

Probability = 15/36 = 5/12
  [#permalink] 28 Nov 2005, 05:35
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Two fair dices are rolled. Find the probability that the

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