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Two measuring scales R and S. When R is 6, S is 30 ; when R

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Two measuring scales R and S. When R is 6, S is 30 ; when R [#permalink] New post 09 Oct 2003, 20:02
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Two measuring scales R and S. When R is 6, S is 30 ; when R is 24, S is 60. How much is R when S is 100?

thanks
praetorian
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 [#permalink] New post 09 Oct 2003, 21:12
araspai wrote:
R=80??


Dont have a "consensus" answer for this..

if you all can show your work, that will be a better way to check your answer

thanks
praetorian
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 [#permalink] New post 09 Oct 2003, 21:49
For every R magnitude increase of 4 times , S magnitude increases X2
R= 6 S = 30
R= 24 , S =60
R = 96 , S = 120

Hence for S = 100 , R = 96*100/96 =80.
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 [#permalink] New post 09 Oct 2003, 23:06
See, it is difficult to define a relationship with two sets of value. I assumed it to be a linear relationship.Made 2 =ns

6a+b=30
24a+b=60 solve for a and b; a= 5/3; b=20 Therefore, for S=100; R=48
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 [#permalink] New post 10 Oct 2003, 04:53
R = 60.

We're looking for rate in change of R with respect to S, and vice versa depending on the value given.

Rate = (R2 - R1) / (S2 - S1)
= (24 - 6) / (60 - 30)
= 18 / 30
= 0.6

Prediction:
R3 = S3 * Rate
R3 = 100 * 0.6
R3 = 60
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 [#permalink] New post 10 Oct 2003, 15:24
Quote:
Prediction:
R3 = S3 * Rate


I disagree with you here.

When We are saying that rate of change is constant, then we can't multiply by values. Here the approach could have been

Since we know that rate of change of R / Rate of change of S = 0.6.

(R3-6) /(S3-6) = 0.6 should also be true. and also

(R3-24)/(S3-60) =0.6 be true.

Here R3,S3 are unknown and 100 respectively.

If we solve any of the two above R3 comes as 48. This is based on assumption that Rate of change remains constant and R & S has a linear relation. If you assume that R ans S vary as their squares. We'll have foll. 2 eqns.
6^2a + b = 30
and 24^2a + b = 60.

Then for S=100, R = 36.

Hence, I think we are missing something in this question.
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 [#permalink] New post 10 Oct 2003, 19:52
We have as many solutions as posts..But this is how the question is posted..

AKAMAI , can you please help?

Thanks
Praetorian
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Re: PS : Scales [#permalink] New post 10 Oct 2003, 23:48
praetorian123 wrote:
Two measuring scales R and S. When R is 6, S is 30 ; when R is 24, S is 60. How much is R when S is 100?

thanks
praetorian


This is an absurd question. First of all, there is no reason or justification to assume, based on the wording of the problem, that any relationship exists whatsoever between R and S. For all we know, these could be random numbers.

Even if we assume that there is, in fact, some relationship between R and S, there are an INFINITE number of equations that can relate R and S based on a sample set of TWO and no reason or justification to assume that the relationship is linear.
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

Re: PS : Scales   [#permalink] 10 Oct 2003, 23:48
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Two measuring scales R and S. When R is 6, S is 30 ; when R

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