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two number are selected from the numbers 3, 4,6,8,10,12,14,

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Director
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two number are selected from the numbers 3, 4,6,8,10,12,14, [#permalink] New post 13 Feb 2006, 14:51
two number are selected from the numbers 3, 4,6,8,10,12,14, what is the probability that the sum of the two numbers selected at random is odd?
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 [#permalink] New post 13 Feb 2006, 15:06
Select 2 Numbers in 7C2 ways.
There are only 6 cases where the sum can be odd, i.e. when "3" is picked.

= 6 /(7C2)
= 6 / [(7*6)/2]
= 6/21
= 2/7
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 [#permalink] New post 13 Feb 2006, 16:17
cJackSparrow wrote:
Select 2 Numbers in 7C2 ways.
There are only 6 cases where the sum can be odd, i.e. when "3" is picked.

= 6 /(7C2)
= 6 / [(7*6)/2]
= 6/21
= 2/7


aye aye sire! :lol:

Agree with Capt. JS
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 [#permalink] New post 13 Feb 2006, 21:09
two numbers are odd when we have 0dd + even

odd numebrs: 3 -> 1 number
Even numbers = 4,6,8,10,12,14 --> 6 numbers

# of ways to pick odd number = 1
# of ways to pick even number = 6C1 = 6

# of ways to get odd number = 6
# of ways to pick any 2 number = 7C2 = 21

P = 6/21 = 2/7
Director
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 [#permalink] New post 13 Feb 2006, 21:26
cJackSparrow wrote:
Select 2 Numbers in 7C2 ways.
There are only 6 cases where the sum can be odd, i.e. when "3" is picked.

= 6 /(7C2)
= 6 / [(7*6)/2]
= 6/21
= 2/7

Good explanation)) agree 2/7
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 [#permalink] New post 18 Feb 2006, 15:05
2/7 is oa , excellent explanations
  [#permalink] 18 Feb 2006, 15:05
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two number are selected from the numbers 3, 4,6,8,10,12,14,

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