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Re: Two numbers are in the ratio of 2:3 . if 4 is added in both numbers [#permalink]
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Forget conventional ways of solving math questions. In PS, IVY approach is the easiest and quickest way to find the answer.


Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers.

A 8

B 6

C 4

D 2

E 10




Let two numbers be a and b.

Since a:b=2:3, we have 2b=3a --> a=2k and b=3k.

So the difference of a and b is k(=3k-2k).

By the assumption in the question we have (2k+4):(3k+4) = 5:7.

That means 5*(3k+4)=7*(2k+4) ---> 15k+20=14k+28 ---> k=8.

The answer is, therefore, A.
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Re: Two numbers are in the ratio of 2:3 . if 4 is added in both numbers [#permalink]
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As after adding 4 numbers ratio becomes 5:7 so i checked for [5:7] * 2 or 3 or 4 so for 4, 20-4/28-4=16/24=2/3 so required numbers are 20 & 28 so difference is 8 option A
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Re: Two numbers are in the ratio of 2:3 . if 4 is added in both numbers [#permalink]
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Hi ramajha,

Your approach is also valid. When dealing with ratio questions on the GMAT, there are usually more ways than you might realize to get to the correct answer (some Tactical, some Algebraic, and some that are just 'brute force' arithmetic). Since no-one will ever know how you got the correct answer, you should use whatever approach you find to be fastest/easiest.

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Re: Two numbers are in the ratio of 2:3 . if 4 is added in both numbers [#permalink]
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ske wrote:
Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers.

A. 8
B. 6
C. 4
D. 2
E. 10


\(\frac{2x + 4}{3x + 4} = \frac{5}{7}\)

Or, \(14x + 28 = 15x + 20\)

Or, \(x = 8\)

Now, we know \(3x - 2x = x = 8\)

So, The answer must be (A) 8
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Re: Two numbers are in the ratio of 2:3 . if 4 is added in both numbers [#permalink]
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ske wrote:
Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers.

A. 8
B. 6
C. 4
D. 2
E. 10

adding 4 numbers ratio becomes 5:7 so i checked for [5:7] * 2 or 3 or 4 so for 4, 20-4/28-4=16/24=2/3 so required numbers are 20 & 28 so difference is 8 option A
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Two numbers are in the ratio of 2:3 . if 4 is added in both numbers [#permalink]
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ske wrote:
Two numbers are in the ratio of 2:3 . if 4 is added in both numbers the ratio becomes 5:7. Find the difference between numbers.

A. 8
B. 6
C. 4
D. 2
E. 10

I solved similarly to Abhishek009 , with one different step.

\(\frac{2x + 4}{3x +\\
4}\) = \(\frac{5}{7}\). Cross multiply to get

14x + 28 = 15x + 20

x = 8, which is the multiplier for the original ratio

So original ratio is

\(\frac{(2)(8)}{(3)(8)}\) = \(\frac{16}{24}\) (Don't reduce - need original #s)

24 - 16 = 8

Answer A
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Re: Two numbers are in the ratio of 2:3 . if 4 is added in both numbers [#permalink]
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Re: Two numbers are in the ratio of 2:3 . if 4 is added in both numbers [#permalink]
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