I'm not really understanding this, but answer is 99/200.
Let me try to explain this:
I suppose if we break it down into little simple form.....
Probability of selecting same numbers with replacement: P = (100/100)X(1/100) = 1/100
Now, probability of selecting different numbers with replacement = 1- (1/100) = 99/100
Now, probability of selecting TWO numbers when 1st one selected is bigger-
99/100 - includes both probabilities of selection either first one as bigger or smaller (In, TWO possible ways selection can be done with replacement)............so selection of first one ALWAYS bigger simply multiply (only half of the time) 0.5 to 99/100 = 99/200
I hope this will help!