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Two numbers when divided by a certain divisor leave

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Two numbers when divided by a certain divisor leave [#permalink] New post 29 Sep 2003, 21:06
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Two numbers when divided by a certain divisor leave remainders of 431 and 379 respectively. When the sum of these two numbers is divided by the same divisor, the remainder is 211. What is the divisor?

(1) 599 (2) 1021 (3) 263 (4) Cannot be determined
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 [#permalink] New post 30 Sep 2003, 21:04
a = nk + 431
b = nj + 379

Now, a+b = n(k+j)+ 431 +379
= n(k+j) + 599 +211
Given 211 is remainder, so n can be 599 or some factor of 599.
Choices tell that it is 599.
  [#permalink] 30 Sep 2003, 21:04
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