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Two oil cans,X and Y,are right circular cylinders,and the he [#permalink]
21 Jan 2013, 02:41
100% (01:31) correct
0% (00:00) wrong based on 24 sessions
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Two oil cans,X and Y,are right circular cylinders,and the height and the radius of Y are both twice those of X.if the oil can X,which is filled to capacity,sells for $2,them at the same rate,how much does the oil can Y sell for if Y is filled to only half its capacity?
Re: Two oil cans,X and Y,are right circular cylinders,and the he [#permalink]
21 Jan 2013, 02:51
Let us suppose the radius and height of can X are r and h respectively. So the radius and height of can Y will be 2r and 2h respectively. Volume of X = 3.14 * r^2 * h Volume of Y = 3.14 * (2r)^2 * 2h = 8 * 3.14 * r^2 * h = 8 times of X's volume. Since X is sold for $2, and Y is filled to only half of its capacity, Y will be sold for 4 * $2 ( half of Y's volume = 8/2 * X's volume ) = $8. Hence E is the answer. Please provide Kudos if you like my explanation.
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