Find all School-related info fast with the new School-Specific MBA Forum

It is currently 21 Aug 2014, 18:11

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Two polar bears are now at points A and B. The two bears are

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
GMAT Instructor
avatar
Joined: 04 Jul 2006
Posts: 1270
Location: Madrid
Followers: 23

Kudos [?]: 120 [0], given: 0

Two polar bears are now at points A and B. The two bears are [#permalink] New post 09 Jul 2006, 04:03
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Two polar bears are now at points A and B. The two bears are travelling at the same constant speed in different directions, as shown in the drawing attached. Approximately how far apart in miles will the bears be when they are at points A´ and B´, if the distance from A to B is 3 miles ?

(A) 1.6 (B) 1.8 (C) 2.0 (D) 2.2 (E) 2.4
Attachments

Polar bears.doc [24.5 KiB]
Downloaded 69 times

To download please login or register as a user


Last edited by kevincan on 10 Jul 2006, 23:10, edited 1 time in total.
Manager
Manager
User avatar
Joined: 19 Apr 2006
Posts: 231
Followers: 1

Kudos [?]: 1 [0], given: 0

GMAT Tests User
 [#permalink] New post 10 Jul 2006, 16:50
Kevin,

I have attached a file...

I need a hint...please....

C = (3+x) = sqrt(3)*x

but I also feel like this has to do with some ratio...
what am I missing?

thank in advance...
Attachments

bear.doc [30.5 KiB]
Downloaded 40 times

To download please login or register as a user

Manager
Manager
avatar
Joined: 26 Jun 2006
Posts: 154
Followers: 1

Kudos [?]: 0 [0], given: 0

 [#permalink] New post 10 Jul 2006, 17:03
I got to the same point!

3+x = x*sqrt(3)

=> x = 3/(sqrt(3)-1)

From here I can even find BA' = 6/(sqrt(3)-1)

But I am missing something to get to A'B' distance. Huh?
VP
VP
User avatar
Joined: 02 Jun 2006
Posts: 1270
Followers: 2

Kudos [?]: 36 [0], given: 0

GMAT Tests User
 [#permalink] New post 10 Jul 2006, 17:26
I got to the same point as both of you...where the distance from B to the intersection of the perpendicular from A' to the horizontal is
3/(sqrt(3)-1)

Couldn't get beyond that...
Manager
Manager
avatar
Joined: 20 Jun 2005
Posts: 151
Followers: 1

Kudos [?]: 8 [0], given: 0

 [#permalink] New post 10 Jul 2006, 22:20
v1rok wrote:
I got to the same point!

3+x = x*sqrt(3)

=> x = 3/(sqrt(3)-1)

From here I can even find BA' = 6/(sqrt(3)-1)

But I am missing something to get to A'B' distance. Huh?


A'B' - ?

BB' = AA'.

AA' = sqrt(2) * sqrt(3) * x = sqrt(6) * x

BA' = 2*x.

A'B' = BB' - BA' = AA' - BA' = x * (sqrt(6) - 2 ) = 3*(sqrt(6) - 2 ) / (sqrt(3)-1)

But A'B' is not from answer list ....
GMAT Instructor
avatar
Joined: 04 Jul 2006
Posts: 1270
Location: Madrid
Followers: 23

Kudos [?]: 120 [0], given: 0

 [#permalink] New post 10 Jul 2006, 23:07
What if you use these approximations?

sqr root (3)=7/4
sqr. root (5)=9/4
sqr root (6) =2.45=49/20 THESE ARE NICE TO KNOW
sqr root (7)=8/3

3*(sqrt(6) - 2 ) / (sqrt(3)-1) =3(0.45)/(3/4)= 5.4/3=1.8

I've changed the question to include the word "approximately" to make it clear that we are looking for the best answer.

Excellent work! I thought everybody had something against polar bears, and as a Canadian, I was a bit hurt :cry:
Manager
Manager
avatar
Joined: 26 Jun 2006
Posts: 154
Followers: 1

Kudos [?]: 0 [0], given: 0

 [#permalink] New post 11 Jul 2006, 09:38
Ahhh! The key was that the bears were traveling at THE SAME CONSTANT SPEED, so they should cover the same distance in the same amount of time, so AA'=BB'! I was consumed by the drawing, I completely forgot about the speed condition!
VP
VP
User avatar
Joined: 02 Jun 2006
Posts: 1270
Followers: 2

Kudos [?]: 36 [0], given: 0

GMAT Tests User
 [#permalink] New post 11 Jul 2006, 09:41
Aha!!! :-)

Good point... Great Question Kevincan!

v1rok wrote:
Ahhh! The key was that the bears were traveling at THE SAME CONSTANT SPEED, so they should cover the same distance in the same amount of time, so AA'=BB'! I was consumed by the drawing, I completely forgot about the speed condition!
Manager
Manager
User avatar
Joined: 19 Apr 2006
Posts: 231
Followers: 1

Kudos [?]: 1 [0], given: 0

GMAT Tests User
 [#permalink] New post 11 Jul 2006, 15:20
kevincan wrote:
What if you use these approximations?

sqr root (3)=7/4
sqr. root (5)=9/4
sqr root (6) =2.45=49/20 THESE ARE NICE TO KNOW
sqr root (7)=8/3

3*(sqrt(6) - 2 ) / (sqrt(3)-1) =3(0.45)/(3/4)= 5.4/3=1.8

I've changed the question to include the word "approximately" to make it clear that we are looking for the best answer.

Excellent work! I thought everybody had something against polar bears, and as a Canadian, I was a bit hurt :cry:


I need to read the question more carefully...
nice question...will make a note of the square root values
  [#permalink] 11 Jul 2006, 15:20
    Similar topics Author Replies Last post
Similar
Topics:
4 Experts publish their posts in the topic There are 9 teddy-bears in a toy store of two sizes: small nafishasan60 4 05 Feb 2012, 22:30
Bear alimad 7 25 Jun 2008, 18:39
1 There are six cards bearing numbers 2,4,5,5,5,6. If two sondenso 5 11 May 2008, 23:11
What is the probability of bearing two boys from four born Vlad77 6 06 Aug 2007, 09:19
Bearing Point, Inc. artshep 0 07 Apr 2007, 16:40
Display posts from previous: Sort by

Two polar bears are now at points A and B. The two bears are

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.