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Two rectangles have the same breadth and the difference

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Intern
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Joined: 27 Sep 2011
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Kudos [?]: 35 [0], given: 9

Two rectangles have the same breadth and the difference [#permalink]

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New post 01 May 2012, 02:36
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

71% (02:06) correct 29% (00:36) wrong based on 14 sessions

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Two rectangles have the same breadth and the difference between their perimeters is 56m. If the difference between their areas is 336m^2, find the breadth of the rectangles.

A. 18
B. 10
C. 24
D. 12

Source: Mathematics by L.Harwood Clarke ( page: 168, No.11)
[Reveal] Spoiler: OA

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Intern
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Joined: 25 Apr 2012
Posts: 16
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Kudos [?]: 10 [0], given: 1

Re: Two rectangles have the same breadth.... [#permalink]

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New post 01 May 2012, 02:44
Let the common breadth be 'b'
and lengths be x and y
Diff. of perimeters = 2(x+b) - 2(y+b) = 2(x-y) = 56
=> x-y = 28
Diff. of areas = bx - by = b(x-y) = 336
=> b = 336/28 = 12
Answer "D"
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Ravi Sankar Vemuri

Re: Two rectangles have the same breadth....   [#permalink] 01 May 2012, 02:44
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Two rectangles have the same breadth and the difference

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