Hi, there. I'm happy to help with this.

Big idea #1:

(even) + (even) = even

(odd) + (odd) = even

but . . .

(odd) + (even) = odd

There are nine combinations here (any of the three of the first set with any of the three of the second set). The results are shown in the matrix attached (odds = green, evens = red).

Of the nine cases, five are odd.

Therefore, the answer = C

Does this make sense? Please let me know if anyone reading this has any questions on what I've said.

Mike

Attachments

matrix of odd & even sums.JPG [ 15.37 KiB | Viewed 1485 times ]

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Mike McGarry

Magoosh Test Prep