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Value in quadratic equation

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Manager
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Value in quadratic equation [#permalink] New post 17 Jun 2009, 17:09
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Please, explain why. Thank you.

Q5:
If (y+3)(y-1) – (y-2)(y-1) = r(y-1), what is the value of y?
(1) r2 = 25
(2) r = 5

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Senior Manager
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Re: Value in quadratic equation [#permalink] New post 18 Jun 2009, 06:32
Quote:
Q5:
If (y+3)(y-1) – (y-2)(y-1) = r(y-1), what is the value of y?
(1) r2 = 25
(2) r = 5


(y+3)(y-1) – (y-2)(y-1) ==>(y-1)((y+3)-(y-2))==>(y-1)(y+3-y+2)
(y-1)5=r(y-1)

Hence Both A and B alone are suff.

Hence D
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Re: Value in quadratic equation [#permalink] New post 18 Jun 2009, 07:19
Seems to be a weird Q. Source Please?

You can actually derive r=5 from the given eq

2 does not add any thing

1 gives 2 more r values

Together also does not help. Hence E
Re: Value in quadratic equation   [#permalink] 18 Jun 2009, 07:19
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