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value of A+B? and GCD=1 [#permalink]
 08 Oct 2008, 04:44
stragedy?
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a plus b and gcd.JPG [ 10.31 KiB | Viewed 345 times ]
Last edited by blover on 08 Oct 2008, 09:06, edited 1 time in total.
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Re: value of A+B and GCD [#permalink]
08 Oct 2008, 05:25
Please, take this with a grain of salt: 1 Not suff. 2 unknows and 1 equation 2 Not suff. a=3, b=5 and a=5, b=3 1+2 Here is my doubt: I'd say both of them are not suff. but maybe I'm missing something... OA? Cheers
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Re: value of A+B? and GCD=1 [#permalink]
08 Oct 2008, 09:28
Assuming a/b = 5/8 and GCD of both numbers = 1 then a=5 and b=8 which then gives a+b = 13
So I think both I and II are needed.
thanks
SM
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Re: value of A+B? and GCD=1 [#permalink]
08 Oct 2008, 12:42
Was going to say E. but smahamkl's answer changed my mind.  Has to be D. a and b cannot be anything other than 5 and 8 respectively.
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Re: value of A+B? and GCD=1 [#permalink]
08 Oct 2008, 12:56
If a and b are positive integers, what is the value of a + b?
(1) a/b = 5/8
(2) GCD(a,b) = 1
(2) GCD(a,b) =1
Obviously insufficient.
However, this tell us that a and b do not have same factors.
(1) 8a = 5b
(2^3)a = 5b
Many possible combinations of a and b. Insufficient.
(1) & (2)
(2^3)a = 5b
Since GCD(a,b) = 1, a must be 5 and b must be 2^3
Sufficient.
The answer is C.
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Re: value of A+B? and GCD=1 [#permalink]
09 Oct 2008, 04:19
1
This post received
KUDOS
A:
a/b = 5/8 so a + b = 13
a/b = 10/16 so a + b = 26
a/b = 15/24 so a + b = 39
so we get multiple values of a+ b , not suffiecient
B: GCD is 1 mean there is no common factor between A and B other than 1 , but this alon is not sufficient as there are thousand such number pair (3,7) , (5,11)...and so on
So B is also not sufficient
---
A + B :
We know ratio is 5/8 and GCD is 1 means they must be 5 and 8 only (if we take 10 and 16 then ratio will remain same but GCD become 2)
So answer will be C:
Thanks
Vishal Shah
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Re: value of A+B? and GCD=1
[#permalink]
09 Oct 2008, 04:19
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