You have not posted the table but here is the solution anyway

\(\frac{75y+87z}{y+z}=84\), this is totScores/ totNumbers.Rewrite it:

\(75y+87z=84y+84z\)

\(3z=9y\) every pair that respect this is valid

z=3 y=1

\(\frac{75+87*3}{4}=84\)

z=36 y=12

\(\frac{75*12+87*36}{40}=84\)

with the table: Value of y Value of z

18<-y

27

36

42

54<-z

72

Hope it's clear, let me know

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