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# Veritas Prep 10 Year Anniversary Promo Question #7

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Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:00
Expert's post
5
This post was
BOOKMARKED
00:00

Difficulty:

55% (hard)

Question Stats:

38% (01:27) correct 63% (00:39) wrong based on 115 sessions

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Veritas Prep 10 Year Anniversary Promo Question #7

One quant and one verbal question will be posted each day starting on Monday Sept 17th at 10 AM PST/1 PM EST and the first person to correctly answer the question and show how they arrived at the answer will win a free Veritas Prep GMAT course ($1,650 value). Winners will be selected and notified by a GMAT Club moderator. For more questions and details please check here: veritas-prep-10-year-anniversary-giveaway-138806.html To participate, please make sure you provide the correct answer (A,B,C,D,E) and explanation that clearly shows how you arrived at it. Winners will be announced the following day at 10 AM Pacific/1 PM Eastern Time. What is the value of integer $$z$$? (1) $$z$$ is the remainder when positive integer y is divided by positive integer $$(y - 1)$$ (2) $$y$$ is not a prime number [Reveal] Spoiler: OA _________________  Veritas Prep GMAT Discount Codes Magoosh Discount Codes e-GMAT Discount Codes Math Expert Joined: 02 Sep 2009 Posts: 34902 Followers: 6506 Kudos [?]: 83148 [1] , given: 10144 Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink] ### Show Tags 20 Sep 2012, 10:01 1 This post received KUDOS Expert's post 1 This post was BOOKMARKED We have a winner! Winner: AbhiJ Official Explanation: Answer is C This question is a classic “Why Are You Here?” question. Statement 1 may look sufficient if you pick numbers (8 and 7; 15 and 14; 5 and 4 → the remainder is always 1). But what about 2 and 1? There’s no remainder there, so z would equal 0. This is why statement 2 is so important. Alone, it’s useless...so why is it there? Statement 2 tells us that (y - 1) cannot be 1, because y cannot be 2. This takes away that one flaw with statement 1, and means that both statements together are sufficient. But of more strategic importance, statement 2 should alert you to that problem with statement 1. Most test-takers miss that flaw when looking at statement 1 alone, but astute test-takers will reconsider once statement 2 is presented. _________________ Director Joined: 24 Aug 2009 Posts: 504 Schools: Harvard, Columbia, Stern, Booth, LSB, Followers: 15 Kudos [?]: 637 [0], given: 241 Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink] ### Show Tags 20 Sep 2012, 10:03 What is the value of integer z? (1) z is the remainder when positive integer y is divided by positive integer (y - 1) (2) y is not a prime number Answer is C 1 insufficient as remainder can be 1, 2 2) insufficient 3) both sufficient _________________ If you like my Question/Explanation or the contribution, Kindly appreciate by pressing KUDOS. Kudos always maximizes GMATCLUB worth -Game Theory If you have any question regarding my post, kindly pm me or else I won't be able to reply Manager Joined: 31 Oct 2011 Posts: 50 Concentration: General Management, Entrepreneurship GMAT 1: 710 Q50 V35 GPA: 3.4 WE: Accounting (Commercial Banking) Followers: 0 Kudos [?]: 15 [0], given: 7 Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink] ### Show Tags 20 Sep 2012, 10:04 My answer is C. (1) if y = 1 or 2 => can't determine z (2) nothing to determine z (1) + (2): y > 3 & y : (y-1) always has reminder 1 Moderator Joined: 10 May 2010 Posts: 825 Followers: 25 Kudos [?]: 391 [1] , given: 192 Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink] ### Show Tags 20 Sep 2012, 10:04 1 This post received KUDOS Stmt 1 is not sufficient as r=1 when y= 3,4,5 and r=0 when y = 2 Stmt 2 is not suff Combine Answer C as y=!2 hence r is always = 1 _________________ The question is not can you rise up to iconic! The real question is will you ? Intern Joined: 05 Jun 2012 Posts: 22 Followers: 0 Kudos [?]: 0 [0], given: 3 Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink] ### Show Tags 20 Sep 2012, 10:04 Answer A. It leaves remainder 1. Intern Joined: 20 Sep 2012 Posts: 5 Followers: 0 Kudos [?]: 0 [0], given: 0 Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink] ### Show Tags 20 Sep 2012, 10:05 Option C. Since y-1 is positive.. y has to be atleast 2. now for any y>2, y/y-1 will give 1 as remainder but for Y=2 remainder is 0. however y is not prime.. so can not be 2. hence we know remainder will be 1 from above. Last edited by Manjulika on 20 Sep 2012, 10:46, edited 1 time in total. Manager Joined: 24 Jul 2011 Posts: 76 Location: India Concentration: Strategy, General Management GMAT 1: 670 Q49 V33 WE: Asset Management (Manufacturing) Followers: 3 Kudos [?]: 120 [0], given: 5 Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink] ### Show Tags 20 Sep 2012, 10:05 Bunuel wrote: Veritas Prep 10 Year Anniversary Promo Question #7 One quant and one verbal question will be posted each day starting on Monday Sept 17th at 10 AM PST/1 PM EST and the first person to correctly answer the question and show how they arrived at the answer will win a free Veritas Prep GMAT course ($1,650 value). Winners will be selected and notified by a GMAT Club moderator. For more questions and details please check here: veritas-prep-10-year-anniversary-giveaway-138806.html

To participate, please make sure you provide the correct answer (A,B,C,D,E) and explanation that clearly shows how you arrived at it.
Winners will be announced the following day at 10 AM Pacific/1 PM Eastern Time.

What is the value of integer $$z$$?

(1) $$z$$ is the remainder when positive integer y is divided by positive integer $$(y - 1)$$

(2) $$y$$ is not a prime number

Ans: A

Z = 1

y-1 and y are two consecutive numbers. When divided it will give remainder 1
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:06
A is sufficient as remainder will always be one when we divide two consecutive integers with the higher one as numerator.

B. doesn't lead us to any solution as what is z is not mentioned.
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:07
1
KUDOS
Ans is C
Statement1:
for ex y=2
2/1 then remainder =0
if y=3
3/2 then remainder=1
Not sufficient
Statement2: y can be 1,4,6 ---Not sufficent
By combining both
y cannot be 2,so in all cases remainder will be 1
Hence sufficient
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:08
Bunuel wrote:

Veritas Prep 10 Year Anniversary Promo Question #7

One quant and one verbal question will be posted each day starting on Monday Sept 17th at 10 AM PST/1 PM EST and the first person to correctly answer the question and show how they arrived at the answer will win a free Veritas Prep GMAT course (\$1,650 value). Winners will be selected and notified by a GMAT Club moderator. For more questions and details please check here: veritas-prep-10-year-anniversary-giveaway-138806.html

To participate, please make sure you provide the correct answer (A,B,C,D,E) and explanation that clearly shows how you arrived at it.
Winners will be announced the following day at 10 AM Pacific/1 PM Eastern Time.

What is the value of integer $$z$$?

(1) $$z$$ is the remainder when positive integer y is divided by positive integer $$(y - 1)$$

(2) $$y$$ is not a prime number

(E)
(1) INSUFF because values will be diffrent if y is even or odd so z will vary
(2) insufficient to answer the given question
together also, not possible to figure out z
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:09
Manjulika wrote:
Option A.
Since y-1 is positive.. y has to be atleast 2. now for any y>=2, y/y-1 will give 1 as remainder

I had to click submit button atleast 3 times to post.. some problem with quick reply option?
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:12
What is the value of integer ?

(1) is the remainder when positive integer y is divided by positive integer

(2) is not a prime number

y and y-1 is consequetive integers
so y divided by y-1 results remainder of 1 which is unknown
INSUFFICIENT
2 is clearly INSUFFICIENT
together is also INSUFFICIENT to say the value of z because when y is 1 y-1 will be 0 which cannot be the case and 1 is not a prime

Last edited by SobirovaZulxumor on 20 Sep 2012, 10:31, edited 2 times in total.
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:15
My Ans IS E-

Statement 1-z is the remainder when positive integer y is divided by positive integer (y - 1)- not sufficient the nos can vary
Statement 2- By itself also not sufficient to find Z
Together also not sufficient.
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:17

(1)y/(y-1)=1+1/(y-1); since z is integer so (y-1) must be 1 or -1. But y-1>0. Then,(y-1) must be 1 => z=1=>(1)Sufficient
(2)y is not prime number is not Sufficient.
So A
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:32
What is the value of integer ?

(1) is the remainder when positive integer y is divided by positive integer

(2) is not a prime number
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Statement 1 is sufficient - Y is a positive number so 1, 2,3,......... and Y-1 is also a Positive number, therefore minimum value of Y can be either 2, 3, 4, etc.
... and remainder always be 1, So value of Z is 1
statement 2- Y is not a prime number, Since it is a positive number so it will again the number can be 4, 6 , 8, 9, 10 etc. and Y-1 will always result in 1 less than the number itself... So Remainder will be 1

And Answer is D, both are sufficient
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:37
How can (A)??

(i) what will happen if y=1 ; y/(y-1) = 1/(1-1) = infinity
Z=infinity

(ii) no sufficient data

together also, not possible to find out z
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:38
fameatop wrote:
What is the value of integer z?

(1) z is the remainder when positive integer y is divided by positive integer (y - 1)
(2) y is not a prime number
1 insufficient as remainder can be 1, 2
2) insufficient
3) both sufficient

How remainder can be 2 in statement1...Obviously not possible
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:44
gamelord wrote:
(1) if y = 1 or 2 => can't determine z
(2) nothing to determine z

(1) + (2): y > 3 & y : (y-1) always has reminder 1

If y=1,then y-1=0, which cannot be a postive integer
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Re: Veritas Prep 10 Year Anniversary Promo Question #7 [#permalink]

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20 Sep 2012, 10:49
Numbers of the form (y,y-1) are called coprimes because they have only 1 common factor and that is 1. The only scenario when y divided by y-1 will give a remainder 0 is when y is 2 but since statement says that, y cannot be a prime number. So both the statements together are sufficient to answer the question.
Re: Veritas Prep 10 Year Anniversary Promo Question #7   [#permalink] 20 Sep 2012, 10:49

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