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I first divide the fraction and then multiple getting:
m^9 * p^8 * r^3 (r^3 since doing it this way we have like r terms and exp so I keep the exp)

OA is m^9 * p^8 * r^6, because they multiplied first and then divided. Please explain why we get different answers based on how the questions is solved.

I first divide the fraction and then multiple getting: m^9 * p^8 * r^3 (r^3 since doing it this way we have like r terms and exp so I keep the exp)

OA is m^9 * p^8 * r^6, because they multiplied first and then divided. Please explain why we get different answers based on how the questions is solved.

I guess there is two rules going on at the same time!

Rule 1: When multiplying expressions with the same base, ADD the exp first.
Rule 2: When multiplying expression with the same exp, multiply bases first.

In this case r3 * r3 we have BOTH the same base and same exponent! So I guess when that happens, we add the exponents (like the rule says "first", duh)

FYI...I knew how to do this with no prob BEFORE reading the prep book and confusing me

To answer this question, you may use the following algebric property:

x^y/x^m = x^y . x^-m = x^(y-m)

use this for simplifying the early experession between the square brackets, and then simply multiply the variables [ by summing the exponents ] to arrive at the correct OA answer you provided. If you need me to show you the arithmatic in details, I'll more than glad to do so.

I guess there is two rules going on at the same time!

Rule 1: When multiplying expressions with the same base, ADD the exp first. Rule 2: When multiplying expression with the same exp, multiply bases first.

In this case r3 * r3 we have BOTH the same base and same exponent! So I guess when that happens, we add the exponents (like the rule says "first", duh)

FYI...I knew how to do this with no prob BEFORE reading the prep book and confusing me

If you get confuse - think about this:

r^3*r^3 = r*r*r*r*r*r = r^6 meaning - rule one

r^3*m^3 = r*r*r*m*m*m = (r*m)*(r*m)*(r*m) = (r*m)^3 meaning rule 2

I guess there is two rules going on at the same time!

Rule 1: When multiplying expressions with the same base, ADD the exp first. Rule 2: When multiplying expression with the same exp, multiply bases first.

In this case r3 * r3 we have BOTH the same base and same exponent! So I guess when that happens, we add the exponents (like the rule says "first", duh)

FYI...I knew how to do this with no prob BEFORE reading the prep book and confusing me

The bold is right but u could have the different way to make it as the one used by MGMAT....

(r^2)^3 = r^(2*3) = r^(3*2) = (r^3)^2 = r^6

It's important to keep in mind that both exist ... It's sometimes tested

I first divide the fraction and then multiple getting: m^9 * p^8 * r^3 (r^3 since doing it this way we have like r terms and exp so I keep the exp)

OA is m^9 * p^8 * r^6, because they multiplied first and then divided. Please explain why we get different answers based on how the questions is solved.

I first divide the fraction and then multiple getting: m^9 * p^8 * r^3 (r^3 since doing it this way we have like r terms and exp so I keep the exp)

OA is m^9 * p^8 * r^6, because they multiplied first and then divided. Please explain why we get different answers based on how the questions is solved.

I first divide the fraction and then multiple getting: m^9 * p^8 * r^3 (r^3 since doing it this way we have like r terms and exp so I keep the exp)

OA is m^9 * p^8 * r^6, because they multiplied first and then divided. Please explain why we get different answers based on how the questions is solved.