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Vial V is 2/3 full of a certain solution and vial W, which [#permalink]
08 Mar 2013, 10:16

1

This post received KUDOS

00:00

A

B

C

D

E

Difficulty:

35% (medium)

Question Stats:

63% (02:38) correct
37% (02:20) wrong based on 46 sessions

Vial V is \frac{2}{3} full of a certain solution and vial W, which has 50% more capacity than vial V, is \frac{3}{4} full of the same solution. If half of the solution in vial V is poured into vial W, vial W will be filled to what fraction of its capacity?

(A)\frac{27}{36}

(B)\frac{10}{11}

(C)\frac{11}{12}

(D)\frac{23}{24}

(E)\frac{35}{36}

I was able to solve it in under 2 mins, but curious to know if there is a 10-sec approach?

Re: Vial V is 2/3 full of a certain solution and vial W, which [#permalink]
08 Mar 2013, 12:32

1

This post received KUDOS

Hello,

Let me try helping you with this one.

It is mentioned in the question that the volume of W is 50% larger than the volume of V. Hence, W=\frac{3}{2}*V This implies that V=\frac{2}{3}*W Now, V is filled with 2/3 with the solution and W is filled 3/4 with the solution. Half of the solution in V is filled into W. We need to find the fraction of W that is filled. So, we have to express everything in terms of W.

Half of the solution in V in terms of W is 1/3. When we express that in terms of W, it becomes

half the volume of solution in V=\frac{1}{3}*\frac{2}{3}*W This is added to 3/4 of the volume W. The total volume is (\frac{1}{3}*\frac{2}{3}*W)+(\frac{3}{4}*W)=\frac{35}{36}*W

Hence, the answer is E.

Hope this helps! Let me know if I could help you any further.

megafan wrote:

Vial V is \frac{2}{3} full of a certain solution and vial W, which has 50% more capacity than vial V, is \frac{3}{4} full of the same solution. If half of the solution in vial V is poured into vial W, vial W will be filled to what fraction of its capacity?

(A)\frac{27}{36}

(B)\frac{10}{11}

(C)\frac{11}{12}

(D)\frac{23}{24}

(E)\frac{35}{36}

I was able to solve it in under 2 mins, but curious to know if there is a 10-sec approach?

Re: Vial V is 2/3 full of a certain solution and vial W, which [#permalink]
09 Mar 2013, 03:21

Expert's post

megafan wrote:

Vial V is \frac{2}{3} full of a certain solution and vial W, which has 50% more capacity than vial V, is \frac{3}{4} full of the same solution. If half of the solution in vial V is poured into vial W, vial W will be filled to what fraction of its capacity?

(A)\frac{27}{36}

(B)\frac{10}{11}

(C)\frac{11}{12}

(D)\frac{23}{24}

(E)\frac{35}{36}

I was able to solve it in under 2 mins, but curious to know if there is a 10-sec approach?

Re: Vial V is 2/3 full of a certain solution and vial W, which [#permalink]
12 Aug 2013, 05:47

Let capacity be denoted by "C"

V = C ===> currently filled = 2/3 C Given : Capacity of W is 50% more than V

W = C + 0.5 C = 1.5 C ===> currently filled = 3/4(1.5C)

half of contents of V ==> 2/3C * 1/2 = 2/6C are then poured in W Required to calculate the fraction to which W will be filled after half of contents of V are filled in W 2/6C +3/4(1.5C)/1.5C Solving, we get 35/36

Re: Vial V is 2/3 full of a certain solution and vial W, which [#permalink]
12 Aug 2013, 09:20

megafan wrote:

Vial V is \frac{2}{3} full of a certain solution and vial W, which has 50% more capacity than vial V, is \frac{3}{4} full of the same solution. If half of the solution in vial V is poured into vial W, vial W will be filled to what fraction of its capacity?

(A)\frac{27}{36}

(B)\frac{10}{11}

(C)\frac{11}{12}

(D)\frac{23}{24}

(E)\frac{35}{36}

I was able to solve it in under 2 mins, but curious to know if there is a 10-sec approach?

........... just 30 seconds to solve with this techniques:

Attachments

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_________________

Asif vai.....

gmatclubot

Re: Vial V is 2/3 full of a certain solution and vial W, which
[#permalink]
12 Aug 2013, 09:20