Hello,

Let me try helping you with this one.

It is mentioned in the question that the volume of W is 50% larger than the volume of V. Hence, W=\(\frac{3}{2}\)*V

This implies that V=\(\frac{2}{3}\)*W

Now, V is filled with 2/3 with the solution and W is filled 3/4 with the solution.

Half of the solution in V is filled into W. We need to find the fraction of W that is filled. So, we have to express everything in terms of W.

Half of the solution in V in terms of W is 1/3. When we express that in terms of W, it becomes

half the volume of solution in V=\(\frac{1}{3}\)*\(\frac{2}{3}\)*W

This is added to 3/4 of the volume W.

The total volume is (\(\frac{1}{3}\)*\(\frac{2}{3}\)*W)+(\(\frac{3}{4}\)*W)=\(\frac{35}{36}\)*W

Hence, the answer is E.

Hope this helps! Let me know if I could help you any further.

megafan wrote:

Vial V is \(\frac{2}{3}\) full of a certain solution and vial W, which has 50% more capacity than vial V, is \(\frac{3}{4}\) full of the same solution. If half of the solution in vial V is poured into vial W, vial W will be filled to what fraction of its capacity?

(A)\(\frac{27}{36}\)

(B)\(\frac{10}{11}\)

(C)\(\frac{11}{12}\)

(D)\(\frac{23}{24}\)

(E)\(\frac{35}{36}\)

I was able to solve it in under 2 mins, but curious to know if there is a 10-sec approach?

_________________

Thanks

Kris

Instructor at Aspire4GMAT

Visit us at http://www.aspire4gmat.com

Post your queries

Join our free GMAT course

New blog: How to get that 700+

New blog: Data Sufficiency Tricks

Press Kudos if this helps!