Hello,

Let me try helping you with this one.

It is mentioned in the question that the volume of W is 50% larger than the volume of V. Hence, W=

\frac{3}{2}*V

This implies that V=

\frac{2}{3}*W

Now, V is filled with 2/3 with the solution and W is filled 3/4 with the solution.

Half of the solution in V is filled into W. We need to find the fraction of W that is filled. So, we have to express everything in terms of W.

Half of the solution in V in terms of W is 1/3. When we express that in terms of W, it becomes

half the volume of solution in V=

\frac{1}{3}*

\frac{2}{3}*W

This is added to 3/4 of the volume W.

The total volume is (

\frac{1}{3}*

\frac{2}{3}*W)+(

\frac{3}{4}*W)=

\frac{35}{36}*W

Hence, the answer is E.

Hope this helps! Let me know if I could help you any further.

megafan wrote:

Vial V is \frac{2}{3} full of a certain solution and vial W, which has 50% more capacity than vial V, is \frac{3}{4} full of the same solution. If half of the solution in vial V is poured into vial W, vial W will be filled to what fraction of its capacity?

(A)\frac{27}{36}

(B)\frac{10}{11}

(C)\frac{11}{12}

(D)\frac{23}{24}

(E)\frac{35}{36}

I was able to solve it in under 2 mins, but curious to know if there is a 10-sec approach?

_________________

Thanks

Kris

Instructor at Aspire4GMAT

Visit us at http://www.aspire4gmat.com

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