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# Virginia, Adrienne, and Dennis have taught history for a

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Virginia, Adrienne, and Dennis have taught history for a [#permalink]  31 Jul 2003, 13:32
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Virginia, Adrienne, and Dennis have taught history for a combined total of 96 years. If Virginia has taught for 9 more years than Adrienne and for 9 fewer years than Dennis, for how many years has Dennis taught?

Why am I wrong in my setup?

V= A + 9
A= A
D= V + 9= ( A + 9) + 9

D= A + 18
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Ride em cowboy

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Re: PS: Who can come up with best algebra solution [#permalink]  31 Jul 2003, 13:36
Curly05 wrote:
Virginia, Adrienne, and Dennis have taught history for a combined total of 96 years. If Virginia has taught for 9 more years than Adrienne and for 9 fewer years than Dennis, for how many years has Dennis taught?

Why am I wrong in my setup?

V= A + 9
A= A
D= V + 9= ( A + 9) + 9

D= A + 18

Nothing. Now that you have V, A, and D all in terms of A, is there a relationship among V, A, and D that you can use?
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AkamaiBrah
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MBA, Anderson School of Management, UCLA, Class of 1993

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Akami [#permalink]  31 Jul 2003, 13:38
Yep, express everything in terms of A doesn't work out for some reason, I mean I got the answer using another algebra relationship but this one doesn't work out.
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HI [#permalink]  31 Jul 2003, 13:39
I got the answer using another relationship, but this particular one don't work, I don't know why
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Why not?

V= A + 9
A= A
D= V + 9= ( A + 9) + 9 = A + 18

now V+A+D=96
=> (A+9) + A + (A+18) = 96
=> 3A + 27 = 96
=> 3A = 69
=> A=23

So, V=23+9=32
D= 23+18=41
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The set up is wrong [#permalink]  04 Aug 2003, 09:35
If you write the question right, Denise has thaught 9 years more than Victor- So:
it shouldbe like:
V=a+9
D=v-9
so, the equation is:
a+9a+a+9-9=96
a=29
d=29
v=38
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Seftalibebegim,
If Denise has taught 9 years more than Victor then D is greater than V. Hence it is D-9=V

Your, 2nd equation is not correct.
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