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Walking at 8KMPH From Point A to Point railway station, mike

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Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 09 Oct 2011, 10:53
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Walking at 8KMPH From Point A to Point railway station, mike will miss the train by 5 minutes. If he walks at 10KMPH he will reach the station by 5 minutes early.What is the distance between Point A to Railway station?

A)9KM
B)6.66KM
C)7.25KM
D)12.40KM
E)13KM
[Reveal] Spoiler: OA

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Re: Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 09 Oct 2011, 12:38
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let the distance be x

according to the given condition-

x/8-x/10=10/60
x/40=1/6
x=40/6
x=6.66km

B
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Re: Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 09 Oct 2011, 14:04
8(t+5) = 10(t-5)
8t+40 = 10t-50
=>t = 45 minutes

distance = 8*((45+5)/60)= 8*(5/6) = 6.66 km

Answer is B.
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Re: Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 09 Oct 2011, 23:49
Using RT=D

Distance= 8 km/h * (t+5)m
Distance= 10 km/h * (t-5)m
Therefore, 8 km/h * (t+5)m = 10 km/h * (t-5)m
solving for t is = 45 min

Distance= 8 km/h * (45+5) min
= 8 km/h * 50/60 hr
= 6.66 km
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Re: Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 10 Oct 2011, 01:20
Assume distance is D.
d/8-8/10 = 10/60
10d-8d/80 = 1/6
2d/80 = 1/6
d= 1/6*40
d = 6.66

answer is B
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Re: Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 10 Oct 2011, 06:36
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Expert's post
gopu106 wrote:
Walking at 8KMPH From Point A to Point railway station, mike will miss the train by 5 minutes. If he walks at 10KMPH he will reach the station by 5 minutes early.What is the distance between Point A to Railway station?

A)9KM
B)6.66KM
C)7.25KM
D)12.40KM
E)13KM


Alternatively, don't assume any variables.

Ratio of speed in 2 cases = 8:10 = 4:5
Ratio of time in the 2 cases = 5:4
The difference between the time is total 10 mins so time taken in the two cases must be 50 min and 40 mins respectively.
Distance = 8 km/hr * (50/60) hrs = 6.66 km

You will be surprised how quickly you can solve questions using ratios (and without writing anything down once you get used to it - that probably accounts for a lot of time saving)

To learn more about ratios, check out:
http://www.veritasprep.com/blog/2011/03 ... of-ratios/
http://www.veritasprep.com/blog/2011/03 ... os-in-tsd/
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Karishma
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Re: Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 10 Oct 2011, 12:02
Yes ratioes is quick.
Speed 8:10 => 4:5
So, Time is 5:4.
Bt given diff is 5-(-5) = 10 min
=> Time is 50:40

Hence distance = 8 * 50/60 = 6.67 Km
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http://gmatclub.com/forum/massive-collection-of-verbal-questions-sc-rc-and-cr-106195.html#p832142
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http://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html
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Re: Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 16 Jul 2014, 01:07
distance = rate * time

(1) d = 8km/h * (t+5)
(2) d = 10 km/h * (t-5)

equalize equations: 8 * (t+5) = 10 * (t-5) --> 8t + 40 = 10t - 50 --> 90 = 2t --> 45 = t (in minutes)

now insert into equation (1) or (2): d = 8 km/h * (45+5) --> 8km/h * 5/6 h --> 40/6 km = 6.67 km. B.
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Re: Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 11 Aug 2014, 06:01
VeritasPrepKarishma wrote:
gopu106 wrote:
Walking at 8KMPH From Point A to Point railway station, mike will miss the train by 5 minutes. If he walks at 10KMPH he will reach the station by 5 minutes early.What is the distance between Point A to Railway station?

A)9KM
B)6.66KM
C)7.25KM
D)12.40KM
E)13KM


Alternatively, don't assume any variables.

Ratio of speed in 2 cases = 8:10 = 4:5
Ratio of time in the 2 cases = 5:4
The difference between the time is total 10 mins so time taken in the two cases must be 50 min and 40 mins respectively.
Distance = 8 km/hr * (50/60) hrs = 6.66 km

You will be surprised how quickly you can solve questions using ratios (and without writing anything down once you get used to it - that probably accounts for a lot of time saving)

To learn more about ratios, check out:
http://www.veritasprep.com/blog/2011/03 ... of-ratios/
http://www.veritasprep.com/blog/2011/03 ... os-in-tsd/

Karishma,
Can you please explain how you got that the times must be 40 and 50 minutes?
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Re: Walking at 8KMPH From Point A to Point railway station, mike [#permalink] New post 11 Aug 2014, 21:11
Expert's post
ronr34 wrote:
VeritasPrepKarishma wrote:
gopu106 wrote:
Walking at 8KMPH From Point A to Point railway station, mike will miss the train by 5 minutes. If he walks at 10KMPH he will reach the station by 5 minutes early.What is the distance between Point A to Railway station?

A)9KM
B)6.66KM
C)7.25KM
D)12.40KM
E)13KM


Alternatively, don't assume any variables.

Ratio of speed in 2 cases = 8:10 = 4:5
Ratio of time in the 2 cases = 5:4
The difference between the time is total 10 mins so time taken in the two cases must be 50 min and 40 mins respectively.
Distance = 8 km/hr * (50/60) hrs = 6.66 km

You will be surprised how quickly you can solve questions using ratios (and without writing anything down once you get used to it - that probably accounts for a lot of time saving)

To learn more about ratios, check out:
http://www.veritasprep.com/blog/2011/03 ... of-ratios/
http://www.veritasprep.com/blog/2011/03 ... os-in-tsd/

Karishma,
Can you please explain how you got that the times must be 40 and 50 minutes?


Ratio of time taken is 5:4. This is a difference of 1.
Actually the difference between time taken is 10 mins. This means, actual values have a multiplier of 10.
So time taken must be 5*10 = 50 mins and 4*10 = 40 mins

Read up on ratio scale and actual values on the links given in the post above.
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My Blog

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Re: Walking at 8KMPH From Point A to Point railway station, mike   [#permalink] 11 Aug 2014, 21:11
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