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Re: Was Lisa's salary [#permalink]
05 Jul 2008, 19:49

I get A. We have to find out if l >=2j , where l is lisas salary, and j is julie's salary.

from stat 1, l=j+20,000, in other words, is j+20,000 >=2j --> we get that 20,000 >=j. So, witht this known, no matter what number you pick for j, if you add 20,000 to it to get lisa's salary, you will see that its always at least twice as large.

from stat 2, you only know lisas salary and nothing about julies. insuff

Re: Was Lisa's salary [#permalink]
05 Jul 2008, 23:07

TheBigCheese wrote:

Was Lisa's salary at least twice as much as Julie's annual salary? 1) lisa's annual salary was $20,000 more than Julies annual salary 2) lisa's anual salary was less than $40,000

I think it's C: L>=J is not an assumption, it's a question though. 1: L= J+20 (nothing could be drawn from here) 2: L<40 (nothing too)

Re: Was Lisa's salary [#permalink]
04 Jun 2009, 01:36

TheBigCheese wrote:

DavidArchuleta wrote:

TheBigCheese wrote:

Was Lisa's salary at least twice as much as Julie's annual salary? 1) lisa's annual salary was $20,000 more than Julies annual salary 2) lisa's anual salary was less than $40,000

I think it's C: L>=J is not an assumption, it's a question though. 1: L= J+20 (nothing could be drawn from here) 2: L<40 (nothing too)

L=J+20 and L<40 so J<20 J<20 and L= J+20 so 2J<L

OA is C

Guys, 2J<40, L also <40, how do you know 2J<L? I think the OA wrong! _________________

Re: Was Lisa's salary at least twice as much as Julie's annual [#permalink]
28 Jan 2012, 05:10

Expert's post

Baten80 wrote:

I am confused with this DS. Need clear help.

Was Lisa's salary at least twice as much as Julie's annual salary?

Question: is L\geq{2J}?

(1) Lisa's annual salary was $20,000 more than Julies annual salary --> J=L-20 --> question becomes: is L\geq{2(L-20)}? --> is L\leq{40}? We don't know that. Not sufficient.

Example: L=50 and J=30 --> answer NO; L=40 and J=20 --> answer YES.

(2) Lisa's anual salary was less than $40,000 --> L<40, clearly insufficient as no info about J.

(1)+(2) From (1) question boiled down to: "is L\leq{40}" and (2) says that L<40, so the asnwer is YES. Sufficient.