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Water is leaking out from a cylinder at the rate of 0.31m^3

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Senior Manager
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Water is leaking out from a cylinder at the rate of 0.31m^3 [#permalink] New post 26 Apr 2006, 02:47
Water is leaking out from a cylinder at the rate of 0.31m^3 per minute. 10 minutes later, the water level decreases 0.25 meter, what is the value of the radius of the cylinder?

0.5
1.0
1.5
2.0
2.5
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 [#permalink] New post 26 Apr 2006, 02:54
volume emptied per minute = 0.31

for 10 minutes = 3.1

volume of cylinder = 22/7 * r^2 * l

here l = 0.25

22/7 * r^2 * 0.25 = 3.1

solving the above equation we get

r = 2
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 [#permalink] New post 26 Apr 2006, 03:11
Water leaking out at 0.31 cubic meter/min

10 mintues --> will have leaked 3.1 cubic meters

Volume of cylinder = pi * r^2 * h

3.1 = pi * r^2 * 0.25
pi*r^2 = 12.4
r = 1.9 (approximately 2)
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 [#permalink] New post 27 Apr 2006, 12:30
Yeah, Ans: 2.

Good Q though.
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 [#permalink] New post 27 Apr 2006, 18:33
Agree with 2 :wink:
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 [#permalink] New post 27 Apr 2006, 18:42
Guys, this is an excellent question. I got this one on the real thing a couple weeks ago. Be sure to familiarize yourself with it.
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 [#permalink] New post 27 Apr 2006, 20:41
ywilfred wrote:
Water leaking out at 0.31 cubic meter/min

10 mintues --> will have leaked 3.1 cubic meters

Volume of cylinder = pi * r^2 * h

3.1 = pi * r^2 * 0.25
pi*r^2 = 12.4
r = 1.9 (approximately 2)


Agree with ywildred's working. :-D
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 [#permalink] New post 28 Apr 2006, 10:58
Charlie45 wrote:
Guys, this is an excellent question. I got this one on the real thing a couple weeks ago. Be sure to familiarize yourself with it.


Exact same question? It is a very good question though, I have having trouble finding L but know I understand. Reminds me of HS math questions. Is there are formula for these type of questions, I mean we have rate of change and time.
  [#permalink] 28 Apr 2006, 10:58
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Water is leaking out from a cylinder at the rate of 0.31m^3

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