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# What am I missing, here? If x<0, then the sqrt of -x* the

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Director
Joined: 11 Sep 2006
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What am I missing, here? If x<0, then the sqrt of -x* the [#permalink]  05 Oct 2007, 05:23
What am I missing, here?

If x<0, then the sqrt of -x* the absolute value of x is...

-x
-1
1
x
sqrt of x

Will wait to post the official answer, which I am contesting!
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...there ain't no such thing as a free lunch...

VP
Joined: 08 Jun 2005
Posts: 1147
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Not sure what -x* the asterisk is for,

but you need to know that sqrt(x^2) = |X|

since X < 0 then -(-X) = X

hence:

sqrt(-X^2) = |-X| when x<0

Director
Joined: 11 Sep 2006
Posts: 514
Followers: 2

Kudos [?]: 35 [0], given: 0

Thanks KillerSquirrel - but that it what I got initially. This was just answered a little bit lower on the thread - the answer is actually -x. I assume this is because the stem says x<0 initially...?
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VP
Joined: 08 Jun 2005
Posts: 1147
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Kudos [?]: 133 [0], given: 0

uphillclimb wrote:
Thanks KillerSquirrel - but that it what I got initially. This was just answered a little bit lower on the thread - the answer is actually -x. I assume this is because the stem says x<0 initially...?

Can you please post the original question (print screen and paste) ? I think I'm missing something here.

Thanks
Director
Joined: 11 Sep 2006
Posts: 514
Followers: 2

Kudos [?]: 35 [0], given: 0

Would love to, but I am not at my home computer, wherein lies the results of my GMATprep test... and yes, I'm sorry, the asterisk was meant to indicate "multiply".
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VP
Joined: 08 Jun 2005
Posts: 1147
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Kudos [?]: 133 [0], given: 0

http://www.gmatclub.com/forum/t53242

Yes ! they are correct the answer is indeed -X

what you are missing is that -(-x) = x

so if you get x as the answer and you know that x<0

then -(-x) = x

but you are looking for -(-x) = x

the red marked x !

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