what are the different ways of doing this?
NOW WHAT WOULD BE THE ANSWER, IF THE GROUP ALWAYS INCLUDE A BOY NAMED JOHN.
Case 1:1B (John) + 2G = C(4,2) = 6 ways
Case 2:2B (John + 1B) + 1G = C(6,1)xC(4,1) = 6x4 = 24 ways
Case 3:3B (John + 2B) + 0G = C(6,2) = 15 ways
Thus total = 45 ways.
Who says elephants can't dance?