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I find myself constantly using long division and multiplication for simple things like 13 x 11.

What are some good arithmetic calcs to memorize? I created a 20x20 multiplication table but this seems like a bit much right?

Perfect squares up to 100? \(\sqrt{3}\)? \(\sqrt{5}\)?

I am not really talking about formulas to memorize since you should definitely memorize things like nCr, nPr, sum of all #'s in an evenly spaced set, etc.

Re: What arithmetic should I memorize? [#permalink]

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25 Jun 2009, 22:18

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Fantastic question

This file should give you an idea where you are lacking. I think you should definitely know the squares from 0-10 and preferrably from 10 to 20 as well.

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31 Oct 2009, 09:56

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I'm new here, and try to go through all the topics - this site is a treasure!

Maybe not the right place to share my experience with "multiplication for simple things like 13 x 11", but anyway...if you need to multiply any two-digits number by 11, just sum those digits and put the result in between. For example, 13x11 -> 1+3=4 -> 143 is the result. Or, 36x11 -> 3+6=9 -> the result is 36x11=396.

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31 Oct 2009, 20:21

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Shelen wrote:

I'm new here, and try to go through all the topics - this site is a treasure!

Maybe not the right place to share my experience with "multiplication for simple things like 13 x 11", but anyway...if you need to multiply any two-digits number by 11, just sum those digits and put the result in between. For example, 13x11 -> 1+3=4 -> 143 is the result. Or, 36x11 -> 3+6=9 -> the result is 36x11=396.

It really saves time.

And if it equals more than 10, add a 1 to the first digit

Re: What arithmetic should I memorize? [#permalink]

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09 Jan 2010, 20:05

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Shelen wrote:

I'm new here, and try to go through all the topics - this site is a treasure!

Maybe not the right place to share my experience with "multiplication for simple things like 13 x 11", but anyway...if you need to multiply any two-digits number by 11, just sum those digits and put the result in between. For example, 13x11 -> 1+3=4 -> 143 is the result. Or, 36x11 -> 3+6=9 -> the result is 36x11=396.

Thanks for the tips. I recently downloaded some math apps to learn shortcuts. I plan to use them minimially though given the geometry and other formulas I need to memorize. It really saves time.

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11 Feb 2010, 10:34

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Thanks for sharing the Doc bb...@Shelen & @jeckll...Thanks for the tip but I would like to add some more.

What if u need to multiply 3 digits or 4 didgits by 11...the procedure is same as u mentioned but it would be done like below

For 3 digits 133x11 --> 1 1+3 3+3 3=1463 And for 4 digits 1243x11 --> 1 1+2 2+4 4+3 3=13673

And for 5 digits 15453x11 --> 1 1+5 5+4 4+5 5+3 3=169983 and so on. you can plug other numbers in and check it out.

Hope it helps! _________________

"Don't be afraid of the space between your dreams and reality. If you can dream it, you can make it so." Target=780 http://challengemba.blogspot.com Kudos??

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11 Feb 2010, 22:41

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Guys! I just found another way of checking whether a number is divisible by 8 or not ( the rule is same but another approach or route ). It's for a number with more than two digits.

Let's take 1936 1) First of all check whether last two digits of the number are divisible by 4 or not. For 1936, we do this way 36/4=9

2) If it is divisible by 4 then add the quotient to the 3rd last digit of the number and if the sum of them is divisible by 2 then the whole number is divisible by 8.

--> 9 (quotient)+ 9 ( 3rd digit from right)= 18, and -->18/2=9 So the whole number is divisible by 8.

Once you understand it and do a little practice, you'll find it easy and fast. **You can try other numbers to see whether it is true or not Hope it helps! _________________

"Don't be afraid of the space between your dreams and reality. If you can dream it, you can make it so." Target=780 http://challengemba.blogspot.com Kudos??

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14 Feb 2010, 06:12

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AtifS wrote:

Thanks for sharing the Doc bb...@Shelen & @jeckll...Thanks for the tip but I would like to add some more.

What if u need to multiply 3 digits or 4 didgits by 11...the procedure is same as u mentioned but it would be done like below

For 3 digits 133x11 --> 1 1+3 3+3 3=1463 And for 4 digits 1243x11 --> 1 1+2 2+4 4+3 3=13673

And for 5 digits 15453x11 --> 1 1+5 5+4 4+5 5+3 3=169983 and so on. you can plug other numbers in and check it out.

Hope it helps!

welldone dude, just a small addition which i tried and will help to avoid confusion:

start writing the answer from right hand side in case if the addition of two no. exceeds 10, and add it to consecutive no. on left hand side. try out!! _________________

"Great people don't do different things, they do things differently"

Re: What arithmetic should I memorize? [#permalink]

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14 Feb 2010, 06:21

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AtifS wrote:

Guys! I just found another way of checking whether a number is divisible by 8 or not ( the rule is same but another approach or route ). It's for a number with more than two digits.

Let's take 1936 1) First of all check whether last two digits of the number are divisible by 4 or not. For 1936, we do this way 36/4=9

2) If it is divisible by 4 then add the quotient to the 3rd last digit of the number and if the sum of them is divisible by 2 then the whole number is divisible by 8.

--> 9 (quotient)+ 9 ( 3rd digit from right)= 18, and -->18/2=9 So the whole number is divisible by 8.

Once you understand it and do a little practice, you'll find it easy and fast. **You can try other numbers to see whether it is true or not Hope it helps!

hi, i feel the process is bit complicated as it doesn't give the value of quotient, it just tells you whether no. is divisible by 8. here is another tric, if the no. formed by last three digits is divisible by 8 then the whole no. is divisible by 8.

953360 is divisible by 8 since 360 is divisible by 8, 529418: not divisible as 418 is not divisible by 8.

plug in different values and try. _________________

"Great people don't do different things, they do things differently"

gmatclubot

Re: What arithmetic should I memorize?
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14 Feb 2010, 06:21

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