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What do you think about this problem

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What do you think about this problem [#permalink] New post 17 Apr 2007, 01:09
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What do you think about this problem?
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Re: DS - GMATPrep (remainder) [#permalink] New post 17 Apr 2007, 01:13
nick_sun wrote:
What do you think about this problem?


A.

statement 1 is suff. if n = (k+1)^3, n = (k+1)(k+1)(k+1) in which every term, (k+1), has reminder 1 if divided by k. therefore, all reminders have a product of 1. so suff.

statement 2 is not suff. k =5 but n could be any integers.
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 [#permalink] New post 17 Apr 2007, 01:19
1. n = (k+1)^3 since we don't know what n is nor k, there are too many possiblities - therefore insufficient

2. k = 5 Again, many possiblities (we have no value for n)

Together: if k=5, then n=(5+1)^3 = 6^3 = 216
if n = 216, and k = 5 , we can get the remainder (216/5) so sufficient

My answer is C.
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 [#permalink] New post 17 Apr 2007, 01:27
:lol: Himalayan is absolutely correct - my bad. Sometimes I jump into the dark void that is math without turning on the flashlight. Please disregard my answer it's wrong.
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Re: DS - GMATPrep (remainder) [#permalink] New post 17 Apr 2007, 03:57
Himalayan wrote:
nick_sun wrote:
What do you think about this problem?


A.

statement 1 is suff. if n = (k+1)^3, n = (k+1)(k+1)(k+1) in which every term, (k+1), has reminder 1 if divided by k. therefore, all reminders have a product of 1. so suff.

statement 2 is not suff. k =5 but n could be any integers.


I've got it. Thank you, Himalayan!
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Re: DS - GMATPrep (remainder) [#permalink] New post 17 Apr 2007, 06:35
nick_sun wrote:
What do you think about this problem?


From statement 1 we have n= k^3+ 3k^2 + 3k +1. and we have to fine n/k. that is (k^3+ 3k^2 + 3k +1)/k that is equal to k^2 +3k +3 + 1/k . Also in the question stem it is given that k is >1 so the remainder of n/k is 1. So sufficient

Statement 2 says that k=5. But no information of n is given and hence this statement alone is insuficient.

Hence answere is A.

Javed.

Cheers!
Re: DS - GMATPrep (remainder)   [#permalink] 17 Apr 2007, 06:35
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