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# What fraction of this year's graduating students at a

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07 Apr 2006, 13:17
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What fraction of this year's graduating students at a certain college are males?

1) 33 percent of the males and 20 percent of the females transferred from another college

2) 25 percent transferred from another college

OA is C, but i'm not sure how you can solve given this information. I would think you would need the proportion of males to females (or the actual number)

Thanks in advance for the help

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07 Apr 2006, 14:49
Manager
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07 Apr 2006, 15:31

Not sure how C is the answer
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10 Apr 2006, 09:56
shevy wrote:
Not sure how C is the answer

If A is the number of men and B the number of women,
the combination of (1) and (2) leads to

A/3 + B/5 = (A+B) / 4

20A + 12B = 15 (A+B)
5A = 3B
A/B = 3/5

So 3/8 of the students are male.

If e. g. A = 30, then B = 50. From these 80 students, 1/3 of the
males (-> 10) and 1/5 of the females (-> 10) transferred from
another college. And these 10 + 10 = 20 represent 25% of the
students (-> 80).
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11 Apr 2006, 06:29
1
KUDOS
1) (33/100)M - males who joined from other colleges
(22/100)F - females who joined from other colleges

2) (25/100)(M+F) - males and females who joined from other colleges

combining 1 and 2

(33/100)M + (22/100)F = (25/100)(M+F)

simplifying, M/F = 3/8.

Thus fraction of males M/(M+F) = 3/11

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11 Apr 2006, 09:52
What fraction of this year's graduating students at a certain college are males?

1) 33 percent of the males and 20 percent of the females transferred from another college

2) 25 percent transferred from another college

OA is C, but i'm not sure how you can solve given this information. I would think you would need the proportion of males to females (or the actual number)

Thanks in advance for the help

What is the source of this question?
Director
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11 Apr 2006, 10:13
C it is
Let me try to explain))
33 percent of the males and 20 percent of the females transferred from another college ---->0.33M and 0.20F where M->total male and F->total female

25 percent transferred from another college--->
so 0.33M+0.20F=1/4(M+F)
after simplifying we get 0.32M=0.2F or M/F=8/5
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11 Apr 2006, 10:16
kripalkavi wrote:
1) (33/100)M - males who joined from other colleges
(22/100)F - females who joined from other colleges

2) (25/100)(M+F) - males and females who joined from other colleges

combining 1 and 2

(33/100)M + (22/100)F = (25/100)(M+F)

simplifying, M/F = 3/8.

Thus fraction of males M/(M+F) = 3/11

(22/100)F - females who joined from other colleges Here is a typo)) it should be 20/100! And I used same approach as you))
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11 Apr 2006, 15:59
I am seeing this question atleast 3rd time.

Catch is here Q contains percent and not values. So, by default we have fraction and past of whole (from 100 percent!)
11 Apr 2006, 15:59
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