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# What fraction of this year's graduating students at a

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Intern
Joined: 20 Feb 2006
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What fraction of this year's graduating students at a [#permalink]  07 Apr 2006, 13:17
What fraction of this year's graduating students at a certain college are males?

1) 33 percent of the males and 20 percent of the females transferred from another college

2) 25 percent transferred from another college

OA is C, but i'm not sure how you can solve given this information. I would think you would need the proportion of males to females (or the actual number)

Thanks in advance for the help

Intern
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Manager
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Not sure how C is the answer
Manager
Joined: 20 Nov 2004
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shevy wrote:
Not sure how C is the answer

If A is the number of men and B the number of women,
the combination of (1) and (2) leads to

A/3 + B/5 = (A+B) / 4

20A + 12B = 15 (A+B)
5A = 3B
A/B = 3/5

So 3/8 of the students are male.

If e. g. A = 30, then B = 50. From these 80 students, 1/3 of the
males (-> 10) and 1/5 of the females (-> 10) transferred from
another college. And these 10 + 10 = 20 represent 25% of the
students (-> 80).
VP
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1
KUDOS
1) (33/100)M - males who joined from other colleges
(22/100)F - females who joined from other colleges

2) (25/100)(M+F) - males and females who joined from other colleges

combining 1 and 2

(33/100)M + (22/100)F = (25/100)(M+F)

simplifying, M/F = 3/8.

Thus fraction of males M/(M+F) = 3/11

Senior Manager
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Re: data sufficiency - graduating students at a certain coll [#permalink]  11 Apr 2006, 09:52
What fraction of this year's graduating students at a certain college are males?

1) 33 percent of the males and 20 percent of the females transferred from another college

2) 25 percent transferred from another college

OA is C, but i'm not sure how you can solve given this information. I would think you would need the proportion of males to females (or the actual number)

Thanks in advance for the help

What is the source of this question?
Director
Joined: 09 Oct 2005
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C it is
Let me try to explain))
33 percent of the males and 20 percent of the females transferred from another college ---->0.33M and 0.20F where M->total male and F->total female

25 percent transferred from another college--->
so 0.33M+0.20F=1/4(M+F)
after simplifying we get 0.32M=0.2F or M/F=8/5
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Director
Joined: 09 Oct 2005
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kripalkavi wrote:
1) (33/100)M - males who joined from other colleges
(22/100)F - females who joined from other colleges

2) (25/100)(M+F) - males and females who joined from other colleges

combining 1 and 2

(33/100)M + (22/100)F = (25/100)(M+F)

simplifying, M/F = 3/8.

Thus fraction of males M/(M+F) = 3/11

(22/100)F - females who joined from other colleges Here is a typo)) it should be 20/100! And I used same approach as you))
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Senior Manager
Joined: 24 Jan 2006
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I am seeing this question atleast 3rd time.

Catch is here Q contains percent and not values. So, by default we have fraction and past of whole (from 100 percent!)
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