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What is the area of circle O above?

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Senior Manager
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What is the area of circle O above? [#permalink] New post 25 Aug 2013, 16:45
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

75% (01:58) correct 25% (01:28) wrong based on 76 sessions
Attachment:
circle 2.png
circle 2.png [ 4.3 KiB | Viewed 1378 times ]
What is the area of circle O above?

(A) 24π
(B) 36π
(C) 48π
(D) 64π
(E) 72π

[Reveal] Spoiler:
a real-different sort of problem
[Reveal] Spoiler: OA

_________________

Asif vai.....


Last edited by Bunuel on 25 Aug 2013, 22:20, edited 1 time in total.
Edited the question.
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Re: What is the area of circle O above? [#permalink] New post 25 Aug 2013, 22:23
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Re: What is the area of circle O above? [#permalink] New post 25 Aug 2013, 23:04
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In the Quadilateral(OABC), since Ang(O),Ang(B), and Ang(C) are Right angles, Ang(A) also must be right angle.
(Since sum of interior angles of a Quadilateral = (n-2) * 180 where n = number of sides)


Hence we could say, Quadilateral(OABC) is a Rectangle.

Using the properties of Rectangle, AC = OB = 6

Hence Area of the Circle = Pi* OB^2=
[Reveal] Spoiler:
Pi * 6^2=36Pi
Senior Manager
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Joined: 10 Jul 2013
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Kudos [?]: 227 [0], given: 102

Re: What is the area of circle O above? [#permalink] New post 26 Aug 2013, 00:13
Smallwonder wrote:
In the Quadilateral(OABC), since Ang(O),Ang(B), and Ang(C) are Right angles, Ang(A) also must be right angle.
(Since sum of interior angles of a Quadilateral = (n-2) * 180 where n = number of sides)


Hence we could say, Quadilateral(OABC) is a Rectangle.

Using the properties of Rectangle, AC = OB = 6

Hence Area of the Circle = Pi* OB^2=
[Reveal] Spoiler:
Pi * 6^2=36Pi


it's not locked brother. you can comment here as you did.
Already this post received expert advice. it's not locked...

however , nice solution :) :)
_________________

Asif vai.....

Re: What is the area of circle O above?   [#permalink] 26 Aug 2013, 00:13
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