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(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of the diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

C.

Bunuel, A rhombus and a square with same lengths have different areas? _________________

hope is a good thing, maybe the best of things. And no good thing ever dies.

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

C.

Bunuel, A rhombus and a square with same lengths have different areas?

Good question.

If you squeeze a square along its diagonal you'll get a rhombus. Different rhombuses you'll get while doing that, will have different area. So, the answer to your question is yes.

Re: What is the area of parallelogram ABCD ? 1) AB = BC = CD = [#permalink]

Show Tags

22 Feb 2013, 02:12

Bunuel wrote:

Sachin9 wrote:

Pardon me. I didn't get you, Bunuel..

Are you saying that the square and different shapes of rhombuses with same length will have different areas?

Yes, that's what I'm saying.

ok thanks.. Now 2 questions: 1)if the square and different shapes of rhombuses with same length will have different areas, the square will have the largest area . Guess this is correct.

2)this question seems dubious now to me.. A square is also a parallelogram and even a rhombus is.. so how can we be sure that ABCD is not a square and is a rhombus. _________________

hope is a good thing, maybe the best of things. And no good thing ever dies.

Are you saying that the square and different shapes of rhombuses with same length will have different areas?

Yes, that's what I'm saying.

ok thanks.. Now 2 questions: 1)if the square and different shapes of rhombuses with same length will have different areas, the square will have the largest area . Guess this is correct.

2)this question seems dubious now to me.. A square is also a parallelogram and even a rhombus is.. so how can we be sure that ABCD is not a square and is a rhombus.

Not sure I understand what you are trying to say.

Anyway: From (1) we have that the parallelogram is also a rhombus (because the sides are equal). From (2) we have that the parallelogram is also a rectangle (because the diagonals are equal).

So, our parallelogram is a rhombus AND a rectangle, so it's a square! _________________

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.

HI Bunuel, Square root of 2 is diagonal.

\sqrt{2}, 1,1 form right angle triangle in rectangle. as we follow this rule in GMAT,cant we follow here ,considering length and breadth to be 1 each??

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.

HI Bunuel, Square root of 2 is diagonal.

\sqrt{2}, 1,1 form right angle triangle in rectangle. as we follow this rule in GMAT,cant we follow here ,considering length and breadth to be 1 each??

Next, are you talking about the second statement? What does "\(\sqrt{2}\), 1, 1 form right angle triangle in rectangle" even mean? Or the next sentence in your post? Sorry, don't understand at all what you mean... _________________

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of the diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.

Bunuel,

Since a square is also parallelogram, we have sides of a sq so easily we can find the area. Shouldn't A be sufficient?

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of the diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.

Bunuel,

Since a square is also parallelogram, we have sides of a sq so easily we can find the area. Shouldn't A be sufficient?

Regards, Ravi

For (1) we have a parallelogram with equal sides, so rhombus, not necessarily a square. _________________

Re: What is the area of parallelogram ABCD ? [#permalink]

Show Tags

23 Nov 2014, 05:55

Bunuel, how can we be sure in such questions that AB or BC is a side? I encountered several such questions in gmatclub tests and if I remember correctly, there was a question which consisted of such trick. _________________

If my post was helpful, press Kudos. If not, then just press Kudos !!!

Bunuel, how can we be sure in such questions that AB or BC is a side? I encountered several such questions in gmatclub tests and if I remember correctly, there was a question which consisted of such trick.

We are given that ABCD is a parallelogram (we should trust the order of letters on the GMAT). So AB, BC, CD and DA must be its sides. How else? Can you please given me the links to the questions you are talking about. _________________

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of the diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.

I would really appreciate if a fault in my logic is pointed out.

Statement 1: ABCD is either a square or a rhombus, so different areas. Insufficient.

Statement 2: ABCD is a parallelogram with equal diagonals, so cannot be a rhombus. Possibly a rectangle or a square. Insufficient.

1+2. It must be a square.

Answer C

gmatclubot

Re: What is the area of parallelogram ABCD ?
[#permalink]
09 Sep 2015, 01:08

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