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(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of the diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

C.

Bunuel, A rhombus and a square with same lengths have different areas? _________________

hope is a good thing, maybe the best of things. And no good thing ever dies.

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

C.

Bunuel, A rhombus and a square with same lengths have different areas?

Good question.

If you squeeze a square along its diagonal you'll get a rhombus. Different rhombuses you'll get while doing that, will have different area. So, the answer to your question is yes.

Re: What is the area of parallelogram ABCD ? 1) AB = BC = CD = [#permalink]
22 Feb 2013, 01:12

Bunuel wrote:

Sachin9 wrote:

Pardon me. I didn't get you, Bunuel..

Are you saying that the square and different shapes of rhombuses with same length will have different areas?

Yes, that's what I'm saying.

ok thanks.. Now 2 questions: 1)if the square and different shapes of rhombuses with same length will have different areas, the square will have the largest area . Guess this is correct.

2)this question seems dubious now to me.. A square is also a parallelogram and even a rhombus is.. so how can we be sure that ABCD is not a square and is a rhombus. _________________

hope is a good thing, maybe the best of things. And no good thing ever dies.

Re: What is the area of parallelogram ABCD ? 1) AB = BC = CD = [#permalink]
22 Feb 2013, 01:23

1

This post received KUDOS

Expert's post

Sachin9 wrote:

Bunuel wrote:

Sachin9 wrote:

Pardon me. I didn't get you, Bunuel..

Are you saying that the square and different shapes of rhombuses with same length will have different areas?

Yes, that's what I'm saying.

ok thanks.. Now 2 questions: 1)if the square and different shapes of rhombuses with same length will have different areas, the square will have the largest area . Guess this is correct.

2)this question seems dubious now to me.. A square is also a parallelogram and even a rhombus is.. so how can we be sure that ABCD is not a square and is a rhombus.

Not sure I understand what you are trying to say.

Anyway: From (1) we have that the parallelogram is also a rhombus (because the sides are equal). From (2) we have that the parallelogram is also a rectangle (because the diagonals are equal).

So, our parallelogram is a rhombus AND a rectangle, so it's a square! _________________

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.

HI Bunuel, Square root of 2 is diagonal.

\sqrt{2}, 1,1 form right angle triangle in rectangle. as we follow this rule in GMAT,cant we follow here ,considering length and breadth to be 1 each??

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of a diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.

HI Bunuel, Square root of 2 is diagonal.

\sqrt{2}, 1,1 form right angle triangle in rectangle. as we follow this rule in GMAT,cant we follow here ,considering length and breadth to be 1 each??

Next, are you talking about the second statement? What does "\sqrt{2}, 1, 1 form right angle triangle in rectangle" even mean? Or the next sentence in your post? Sorry, don't understand at all what you mean... _________________

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of the diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.

Bunuel,

Since a square is also parallelogram, we have sides of a sq so easily we can find the area. Shouldn't A be sufficient?

(1) Says that ABCD is a rhombus. Area of rhombus d1*d2/2 (d1 and d2 are the lengths of the diagonals) or b*h (b is the length of the base, h is the altitude (height).) Insufficient

(2) Says that ABCD is a rectangle. Area of a rectangle L*W (length*width) Insufficient.

(1)+(2) ABCD is rectangle and rhombus --> ABCD is square --> Area=1^2=1 or (2^1/2)*(2^1/2)/2=1

Answer: C.

Bunuel,

Since a square is also parallelogram, we have sides of a sq so easily we can find the area. Shouldn't A be sufficient?

Regards, Ravi

For (1) we have a parallelogram with equal sides, so rhombus, not necessarily a square. _________________