What is the area of rectangle ABCD?

1) Diagonal AC is twice as long as side CD

2) Diagonal AC is .1 meters longer side AD

Let AB = x and BC = y

=> AB = CD = x and

BC = AD = y

AC = Sqrt(AB^2 + BC^2) = x^2 + y^2

Area = AB * BC = xy

STAT1:

AC = 2x

=> AC^2 = 4x^2

=> x^2 + y^2 = 4x^2

=> y = sqrt3 * x

But we dont know the value of x and y. SO NOT SUFFICIENT

STAT2:

AC = .1 + AD

sqrt(x^2+y^2) = .1 + y

square and solve we get

x^2 = .01 + .2y

we still don't know what x and y are so NOT SUFFICIENT

Combining STAT1 and STAT2 we have two equations and two unknowns so SUFFICIENT.

Hence, answer will be C.

Hope it helps!

_________________

Ankit

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