Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: DS: Rectangular [#permalink]
17 Feb 2008, 19:15

oh, okay. i had thought that with rectangles, their corners were always 90 degrees. I guess we cant assume that because of shapes like rhombuses, etc ?

edit: wait a sec, if the corners arent 90 degrees, then why can we use pythagorean theorem and say that ^2+b^2 = 5 ?

Re: DS: Rectangular [#permalink]
19 Feb 2008, 00:17

pmenon wrote:

oh, okay. i had thought that with rectangles, their corners were always 90 degrees. I guess we cant assume that because of shapes like rhombuses, etc ?

edit: wait a sec, if the corners arent 90 degrees, then why can we use pythagorean theorem and say that ^2+b^2 = 5 ?

The angles of a rectangle are ALWAYS 90 degrees.

But if the hypo is 5, its not necessary that the other two sides will always be 3 and 4.

Re: DS: Rectangular [#permalink]
20 May 2011, 17:07

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer. _________________

Re: DS: Rectangular [#permalink]
20 May 2011, 17:33

bibhas wrote:

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer.

I meant to say; any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5.

one side: \(2\sqrt{6}\) and other side: \(1\); hypotenuse: \(5\)

\(1^2+(2\sqrt{6})^2=5^2\)

And a square is a specialized rectangle in GMAT. _________________

Re: DS: Rectangular [#permalink]
23 Jun 2011, 10:52

fluke wrote:

bibhas wrote:

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer.

I meant to say; any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5.

one side: \(2\sqrt{6}\) and other side: \(1\); hypotenuse: \(5\)

\(1^2+(2\sqrt{6})^2=5^2\)

And a square is a specialized rectangle in GMAT.

Hi , Your statement "any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5. " is not true if its a right angle traingle with diagonal as 5. as per Pythagoras theorem other 2 sides should be 3 and 4 so A is sufficient alone Pl clarify incase I am missing anything

Re: DS: Rectangular [#permalink]
23 Jun 2011, 11:01

sameershintrein wrote:

fluke wrote:

bibhas wrote:

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer.

I meant to say; any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5.

one side: \(2\sqrt{6}\) and other side: \(1\); hypotenuse: \(5\)

\(1^2+(2\sqrt{6})^2=5^2\)

And a square is a specialized rectangle in GMAT.

Hi , Your statement "any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5. " is not true if its a right angle traingle with diagonal as 5. as per Pythagoras theorem other 2 sides should be 3 and 4 so A is sufficient alone Pl clarify incase I am missing anything

Pythagoras theorem says .. Hyp^2 = sum of the squares of other 2 sides.. it never said the all the sides are phythagoras triplets like 3,4,5 and 9,12,15 so if the hyp = 5, yes its easier to assume that other 2 sides follow the triplet format and are 3 and 4 but nothing stops us from assuming that they can be 1 and 2 sqrt 6.

Re: DS: Rectangular [#permalink]
23 Jun 2011, 11:14

sameershintrein wrote:

fluke wrote:

bibhas wrote:

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer.

I meant to say; any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5.

one side: \(2\sqrt{6}\) and other side: \(1\); hypotenuse: \(5\)

\(1^2+(2\sqrt{6})^2=5^2\)

And a square is a specialized rectangle in GMAT.

Hi , Your statement "any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5. " is not true if its a right angle traingle with diagonal as 5. as per Pythagoras theorem other 2 sides should be 3 and 4 so A is sufficient alone Pl clarify incase I am missing anything

3,4,5 is just one of the infinite possibilities.

Why don't you draw it and see it yourself.

Draw a horizontal line-segment(AB) of 1 unit . Draw a perpendicular ray directly upward from point A. Now, using divider pointing at point B, and setting the divider to 5 units, make a small arc so that it cuts the ray at some point, say C. Join BC. You now have a right triangle with hypotenuse 5, one side 1 unit, and another side \(\sqrt{5^2-1} = \sqrt{24}= 2 \sqrt{6} \approx 4.9\)

Like this, we have infinite possibilities because there are infinite real numbers between 0 and 5, exclusive. _________________

Hello everyone! Researching, networking, and understanding the “feel” for a school are all part of the essential journey to a top MBA. Wouldn’t it be great... ...

As part of our focus on MBA applications next week, which includes a live QA for readers on Thursday with admissions expert Chioma Isiadinso, we asked our bloggers to...

Booth allows you flexibility to communicate in whatever way you see fit. That means you can write yet another boring admissions essay or get creative and submit a poem...