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oh, okay. i had thought that with rectangles, their corners were always 90 degrees. I guess we cant assume that because of shapes like rhombuses, etc ?

edit: wait a sec, if the corners arent 90 degrees, then why can we use pythagorean theorem and say that ^2+b^2 = 5 ?

oh, okay. i had thought that with rectangles, their corners were always 90 degrees. I guess we cant assume that because of shapes like rhombuses, etc ?

edit: wait a sec, if the corners arent 90 degrees, then why can we use pythagorean theorem and say that ^2+b^2 = 5 ?

The angles of a rectangle are ALWAYS 90 degrees.

But if the hypo is 5, its not necessary that the other two sides will always be 3 and 4.

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer. _________________

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer.

I meant to say; any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5.

one side: \(2\sqrt{6}\) and other side: \(1\); hypotenuse: \(5\)

\(1^2+(2\sqrt{6})^2=5^2\)

And a square is a specialized rectangle in GMAT. _________________

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer.

I meant to say; any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5.

one side: \(2\sqrt{6}\) and other side: \(1\); hypotenuse: \(5\)

\(1^2+(2\sqrt{6})^2=5^2\)

And a square is a specialized rectangle in GMAT.

Hi , Your statement "any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5. " is not true if its a right angle traingle with diagonal as 5. as per Pythagoras theorem other 2 sides should be 3 and 4 so A is sufficient alone Pl clarify incase I am missing anything

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer.

I meant to say; any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5.

one side: \(2\sqrt{6}\) and other side: \(1\); hypotenuse: \(5\)

\(1^2+(2\sqrt{6})^2=5^2\)

And a square is a specialized rectangle in GMAT.

Hi , Your statement "any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5. " is not true if its a right angle traingle with diagonal as 5. as per Pythagoras theorem other 2 sides should be 3 and 4 so A is sufficient alone Pl clarify incase I am missing anything

Pythagoras theorem says .. Hyp^2 = sum of the squares of other 2 sides.. it never said the all the sides are phythagoras triplets like 3,4,5 and 9,12,15 so if the hyp = 5, yes its easier to assume that other 2 sides follow the triplet format and are 3 and 4 but nothing stops us from assuming that they can be 1 and 2 sqrt 6.

Your option cannot form a triangle and second option makes the parallelogram a Square (questions says Rectangular region). So neither of them is sufficient enough to justify your answer.

I meant to say; any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5.

one side: \(2\sqrt{6}\) and other side: \(1\); hypotenuse: \(5\)

\(1^2+(2\sqrt{6})^2=5^2\)

And a square is a specialized rectangle in GMAT.

Hi , Your statement "any combination of two positive numbers whose squares add up to 25 i.e. 5^2 will form a triangle with hypotenuse 5. " is not true if its a right angle traingle with diagonal as 5. as per Pythagoras theorem other 2 sides should be 3 and 4 so A is sufficient alone Pl clarify incase I am missing anything

3,4,5 is just one of the infinite possibilities.

Why don't you draw it and see it yourself.

Draw a horizontal line-segment(AB) of 1 unit . Draw a perpendicular ray directly upward from point A. Now, using divider pointing at point B, and setting the divider to 5 units, make a small arc so that it cuts the ray at some point, say C. Join BC. You now have a right triangle with hypotenuse 5, one side 1 unit, and another side \(\sqrt{5^2-1} = \sqrt{24}= 2 \sqrt{6} \approx 4.9\)

Like this, we have infinite possibilities because there are infinite real numbers between 0 and 5, exclusive. _________________

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