What is the area of the circle : PS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 16 Jan 2017, 08:01

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# What is the area of the circle

Author Message
Director
Joined: 19 Mar 2007
Posts: 524
Followers: 3

Kudos [?]: 32 [0], given: 0

What is the area of the circle [#permalink]

### Show Tags

09 Jul 2007, 03:50
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

What is the area of the circle?

Last edited by nick_sun on 28 Jun 2008, 02:32, edited 1 time in total.
Senior Manager
Joined: 28 Feb 2007
Posts: 306
Followers: 1

Kudos [?]: 40 [0], given: 0

### Show Tags

09 Jul 2007, 04:54
C.

Area of equilateral triangle S=[a^2*3^1/2]/4 so a=6

a- side of triangle. R- raduis of circumscribed circle.

R=a/(3^1/2) so R=2*3^1/2 and Pi*R^2=12*Pi.
Senior Manager
Joined: 04 Jun 2007
Posts: 346
Followers: 1

Kudos [?]: 29 [0], given: 0

### Show Tags

09 Jul 2007, 05:48
UMB wrote:
C.

Area of equilateral triangle S=[a^2*3^1/2]/4 so a=6

a- side of triangle. R- raduis of circumscribed circle.

R=a/(3^1/2) so R=2*3^1/2 and Pi*R^2=12*Pi.

That is right.

Radius of circumcircle = a/sqrt(3); a = side of triangle
Radius of incircle = [sqrt(3)*a]/6; a = side of triangle

These formulas are valid for equilateral triangles only!
Senior Manager
Joined: 11 Jun 2006
Posts: 254
Followers: 3

Kudos [?]: 9 [0], given: 0

### Show Tags

09 Jul 2007, 06:17
Is there an easier way to do this? I would think the gmat doesn't want to test the forumula of a circumcircle.
Director
Joined: 19 Mar 2007
Posts: 524
Followers: 3

Kudos [?]: 32 [0], given: 0

### Show Tags

09 Jul 2007, 06:44
UMB wrote:
R=a/(3^1/2) so R=2*3^1/2 and Pi*R^2=12*Pi.

Thank you, UMB! I've got it
09 Jul 2007, 06:44
Display posts from previous: Sort by