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# What is the average (arithmetic mean) height of the n people

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Manager
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What is the average (arithmetic mean) height of the n people [#permalink]  21 Mar 2010, 09:49
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(N/A)

Question Stats:

80% (01:11) correct 20% (01:11) wrong based on 13 sessions
What is the average (arithmetic mean) height of the n people in a certain group?

(1) The average height of the n/3 tallest people in the group is 6 feet 2(1/2) inches, and the average height of the rest of the people in the group is 5 feet 10 inches.

(2) The sum of the heightsof the n people is 178 feet 9 inches.

OA =
[Reveal] Spoiler:
A

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Senior Manager
Joined: 13 Dec 2009
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Kudos [?]: 137 [0], given: 13

Re: Average question [#permalink]  21 Mar 2010, 10:35
nifoui wrote:
What is the average (arithmetic mean) height of the n people in a certain group?

(1) The average height of the n/3 tallest people in the group is 6 feet 2(1/2) inches, and the average height of the rest of the people in the group is 5 feet 10 inches.

(2) The sum of the heightsof the n people is 178 feet 9 inches.

OA =
[Reveal] Spoiler:
A

Stmt1: Avg of n/3 people= 6feet 2(1/2) inches = n/3 * 6feet 2(1/2) inches
Avg of 2n/3 people = 5feet 10 inches = 2n /3*5feet 10 inches
If we add both above quantities and divide it by n we will get the avg since n will cancel out. So, sufficient.

Stmt2: if sum is given to calculate avg we have to divide it by n. But we dont know the value of n so insufficient.
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My debrief: done-and-dusted-730-q49-v40

Manager
Joined: 04 May 2009
Posts: 132
Location: London
Schools: Haas (WL), Kellogg (matricultating), Stanford (R2, ding), Columbia (ding)
WE 1: 3 years hotel industry sales and marketing France
WE 2: 3 years financial industry marketing UK
Followers: 2

Kudos [?]: 29 [0], given: 10

Re: Average question [#permalink]  21 Mar 2010, 11:21
Makes sense indeed, thanks!
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Re: Average question [#permalink]  21 Mar 2010, 12:40
IMO E....from the information provided we don't know what N is.
Senior Manager
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Re: Average question [#permalink]  21 Mar 2010, 22:49
1
KUDOS
Socker121314 wrote:
IMO E....from the information provided we don't know what N is.

but if u see statement 1 you can find out avg without knowing n
Avg = (n/3 * 6feet 2(1/2) inches + 2n /3*5feet 10 inches ) / n
= 1/3 * 6feet 2(1/2) inches + 2 /3*5feet 10 inches
we dont need to convert it and calculate but we can find the value. So answer is A
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My debrief: done-and-dusted-730-q49-v40

Re: Average question   [#permalink] 21 Mar 2010, 22:49
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